CBSE Class 10 Maths Notes Chapter 13 Surface Areas and Volumes Pdf free download is part of Class 10 Maths Notes for Quick Revision. Here we have given NCERT Class 10 Maths Notes Chapter 13 Surface Areas and Volumes. According to new CBSE Exam Pattern,Ā MCQ Questions for Class 10 MathsĀ Carries 20 Marks.

CBSE Class 10 Maths Notes Chapter 13 Surface Areas and Volumes

Surface Areas and Volumes Class 10 Notes Maths Chapter 13 1

SURFACE AREA AND VOLUME OF COMBINATIONS

Cone on a Cylinder.
Surface Areas and Volumes Class 10 Notes Maths Chapter 13 2
r = radius of cone & cylinder;
h1 = height of cone
h2 = height of cylinder
Total Surface area = Curved surface area of cone + Curved surface area of cylinder + area of circular base
= Ļ€rl + 2Ļ€rh2 +Ļ€r2;
Slant height, l = \(\sqrt { { r }^{ 2 }+{ { { h }_{ 1 }^{ 2 } } } }\)
Total Volume = Volume of cone + Volume of cylinder
= \(\frac { 1 }{ 3 } { \pi r }^{ 2 }{ h }_{ 1 }+{ \pi r }^{ 2 }{ h }_{ 2 }\)

Cone on a Hemisphere:
Surface Areas and Volumes Class 10 Notes Maths Chapter 13 3
h = height of cone;
l = slant height of cone = \(\sqrt { { r }^{ 2 }+{ h }^{ 2 } }\)
r = radius of cone and hemisphere
Total Surface area = Curved surface area of cone + Curved surface area of hemisphere = Ļ€rl + 2Ļ€r2
Volume = Volume of cone + Volume of hemisphere = \(\frac { 1 }{ 3 } { \pi r }^{ 2 }h+\frac { 2 }{ 3 } { \pi r }^{ 3 }\)

Conical Cavity in a Cylinder
Surface Areas and Volumes Class 10 Notes Maths Chapter 13 4
r = radius of cone and cylinder;
h = height of cylinder and conical cavity;
l = Slant height
Total Surface area = Curved surface area of cylinder + Area of bottom face of cylinder + Curved surface area of cone = 2Ļ€rh + Ļ€r2 + Ļ€rl
Volume = Volume of cylinder – Volume of cone = \({ \pi r }^{ 2 }h-\frac { 1 }{ 3 } { \pi r }^{ 2 }h=\frac { 2 }{ 3 } { \pi r }^{ 2 }h\)

Cones on Either Side of Cylinder.
Surface Areas and Volumes Class 10 Notes Maths Chapter 13 5
r = radius of cylinder and cone;
h1 = height of cylinder
h2 = height of cones
Slant height of cone, l = \(\sqrt { { h }_{ 2 }^{ 2 }+{ r }^{ 2 } }\)
Surface area = Curved surface area of 2 cones + Curved surface area of cylinder = 2Ļ€rl + 2Ļ€rh1
Volume = 2(Volume of cone) + Volume of cylinder = \(\frac { 2 }{ 3 } { \pi r }^{ 2 }{ h }_{ 2 }+{ \pi r }^{ 2 }{ h }_{ 1 }\)

Cylinder with Hemispherical Ends.
Surface Areas and Volumes Class 10 Notes Maths Chapter 13 6
r = radius of cylinder and hemispherical ends;
h = height of cylinder
Total surface area= Curved surface area of cylinder + Curved surface area of 2 hemispheres = 2Ļ€rh + 4Ļ€r2
Volume = Volume of cylinder + Volume of 2 hemispheres = \({ \pi r }^{ 2 }h+\frac { 4 }{ 3 } { \pi r }^{ 3 }\)

Hemisphere on Cube or Hemispherical Cavity on Cube
Surface Areas and Volumes Class 10 Notes Maths Chapter 13 7
a = side of cube;
r = radius of hemisphere.
Surface area = Surface area of cube – Area of hemisphere face + Curved surface area of hemisphere
= 6a2 – Ļ€r2 + 2Ļ€r2 = 6a2 + Ļ€r2
Volume = Volume of cube + Volume of hemisphere = \({ a }^{ 3 }+\frac { 4 }{ 3 } { \pi r }^{ 3 }\)

Hemispherical Cavity in a Cylinder
Surface Areas and Volumes Class 10 Notes Maths Chapter 13 8
r = radius of hemisphere;
h = height of cylinder
Total surface area = Curved surface area of cylinder + Surface area of base + Curved surface area of hemisphere
= 2Ļ€rh + Ļ€r2 + 2Ļ€r2 = 2Ļ€rh + 3Ļ€r2
Volume = Volume of cylinder – Volume of hemisphere = \({ \pi r }^{ 2 }h-\frac { 2 }{ 3 } { \pi r }^{ 3 }\)

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