Category: CBSE

Get Free NCERT Solutions for Class 10 Maths Chapter 8 Ex 8.3 Introduction to Trigonometry Class 10 Maths NCERT Solutions are extremely helpful while doing homework. Exercise 8.3 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 8 Maths Class 10 Coordinate Geometry Exercise 8.3 Provided in NCERT Textbook.

Topics and Sub Topics in Class 10 Maths Chapter 8 Introduction to Trigonometry:

Section Name	Topic Name
8	Introduction to Trigonometry
8.1	Introduction
8.2	Trigonometric Ratios
8.3	Trigonometric Ratios Of Some Specific Angles
8.4	Trigonometric Ratios Of Complementary Angles
8.5	Trigonometric Identities
8.6	Summary

• Class 10 Maths Introduction to Trigonometry Ex 8.1
• प्रश्नावली 8.1 का हल हिंदी में
• Introduction to Trigonometry Class 10 Ex 8.2
• प्रश्नावली 8.2 का हल हिंदी में
• Introduction to Trigonometry Class 10 Ex 8.3
• प्रश्नावली 8.3 का हल हिंदी में
• Introduction to Trigonometry Class 10 Ex 8.4
• प्रश्नावली 8.4 का हल हिंदी में
• Introduction to Trigonometry Class 10 Extra Questions

You can also download the free PDF of Chapter 8 Ex 8.3 Coordinate Geometry NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

Board	CBSE
Textbook	NCERT
Class	Class 10
Subject	Maths
Chapter	Chapter 8
Chapter Name	Introduction to Trigonometry
Exercise	Ex 8.3
Number of Questions Solved	7
Category	NCERT Solutions

NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3

NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3.

Ex 8.3 Class 10 Maths Question 1.
Evaluate:

Solution:

Ex 8.3 Class 10 Maths Question 2.
Show that:
(i) tan 48° tan 23° tan 42° tan 67° = 1
(ii) cos 38° cos 52° – sin 38° sin 52° = 0
Solution:

Download NCERT Solutions For Class 10 Maths Chapter 8 Introduction to Trigonometry PDF

Ex 8.3 Class 10 Maths Question 3.
If tan 2A = cot (A – 18°), where 2A is an acute angle, find the value of A.
Solution:

Ex 8.3 Class 10 Maths Question 4.
If tan A = cot B, prove that A + B = 90°.
Solution:

Ex 8.3 Class 10 Maths Question 5.
If sec 4A = cosec (A – 20°), where 4A is an acute angle, find the value of A.
Solution:

Ex 8.3 Class 10 Maths Question 6.
If A, B and C are interior angles of a triangle ABC, then show that: sin (\(\frac { B+C }{ 2 }\)) = cos \(\frac { A }{ 2 }\)
Solution:

Ex 8.3 Class 10 Maths Question 7.
Express sin 61° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.
Solution:

NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry (Hindi Medium) Ex 8.3

We hope the NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3, help you. If you have any query regarding NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.3, drop a comment below and we will get back to you at the earliest.

Get Free NCERT Solutions for Class 10 Maths Chapter 15 Ex 15.2 PDF. Probability Class 10 Maths NCERT Solutions are extremely helpful while doing your homework. Exercise 15.2 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 15 Maths Class 10 Probability Exercise 15.2 provided in NCERT TextBook.

Topics and Sub Topics in Class 10 Maths Chapter 15 Probability:

Section Name	Topic Name
15	Probability
15.1	Introduction
15.2	A Theoretical Approach
15.3	Summary

• Probability Class 10 Ex 15.1
• प्रश्नावली 15.1 का हल हिंदी में
• Probability Class 10 Ex 15.2
• प्रश्नावली 15.2 का हल हिंदी में
• Probability Class 10 Extra Questions

You can also download the free PDF of  Ex 15.1 Class 10 Probability NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

Board	CBSE
Textbook	NCERT
Class	Class 10
Subject	Maths
Chapter	Chapter 15
Chapter Name	Probability
Exercise	Ex 15.2
Number of Questions Solved	5
Category	NCERT Solutions

NCERT Solutions For Class 10 Maths Chapter 15 Probability Ex 15.2

NCERT Solutions for Class 10 Maths Chapter 15 Probability Ex 15.2 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 15 Probability Ex 15.2.

Ex 15.2 Class 10 Maths Question 1.
Two customers Shyam and Ekta are visiting a particular shop in the same week (Tuesday to Saturday). Each is equally likely to visit the shop on any day as on another day. What is the probability that both will visit the shop on
(i) the same day?
(ii) consecutive days?
(iii) different days?
Solution:

Download NCERT Solutions For Class 10 Maths Chapter 15 Probability PDF

Ex 15.2 Class 10 Maths Question 2.
A die is numbered in such a way that its faces show the number 1, 2, 2, 3, 3, 6. It is thrown two times and the total score in two throws is noted. Complete the following table which gives a few values of the total score on the two throws:

What is the probability that the total score is at least 6?
(i) even
(ii) 6
(iii) at least 6
Solution:

Ex 15.2 Class 10 Maths Question 3.
A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is doubles that of a red ball, determine the number of blue balls in the bag.
Solution:

Ex 15.2 Class 10 Maths Question 4.
A box contains 12 balls out of which x are black. If one ball is drawn at random from the box, what is the probability that it will be a black ball? If 6 more black balls are put in the box, the probability of drawing a black ball is now double of what it was before. Find x.
Solution:

Ex 15.2 Class 10 Maths Question 5.
A jar contains 24 marbles, some are green and others are blue. If a marble is drawn at random from the jar, the probability that it is green is 2/3. Find the number of blue balls in the jar.
Solution:

NCERT Solutions for Class 10 Maths Chapter 15 Probability (Hindi Medium) Ex 15.2

We hope the NCERT Solutions for Class 10 Maths Chapter 15 Probability Ex 15.2, help you. If you have any query regarding NCERT Solutions for Class 10 Maths Chapter 15 Probability Exercise 15.2, drop a comment below and we will get back to you at the earliest.

Get Free NCERT Solutions for Class 10 Maths Chapter 13 Ex 13.4 PDF. Surface Areas and Volumes Class 10 Maths NCERT Solutions are extremely helpful while doing your homework. Exercise 13.4 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 13 Maths Class 10 Surface Areas and Volumes Exercise 13.4 provided in NCERT TextBook.

Topics and Sub Topics in Class 10 Maths Chapter 13 Surface Areas and Volumes:

Section Name	Topic Name
13	Surface Areas And Volumes
13.1	Introduction
13.2	Surface Area Of A Combination Of Solids
13.3	Volume Of A Combination Of Solids
13.4	Conversion Of Solid From One Shape To Another
13.5	Frustum Of A Cone
13.6	Summary

• Surface Areas and Volumes Class 10 Ex 13.1
• प्रश्नावली 13.1 का हल हिंदी में
• Surface Areas and Volumes Class 10 Ex 13.2
• प्रश्नावली 13.2 का हल हिंदी में
• Surface Areas and Volumes Class 10 Ex 13.3
• प्रश्नावली 13.3 का हल हिंदी में
• Surface Areas and Volumes Class 10 Ex 13.4
• प्रश्नावली 13.4 का हल हिंदी में
• Surface Areas and Volumes Class 10 Ex 13.5
• प्रश्नावली 13.5 का हल हिंदी में
• Surface Areas and Volumes Class 10 Extra Questions

You can also download the free PDF of  Ex 13.4 Class 10 Surface Areas and Volumes NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

Board	CBSE
Textbook	NCERT
Class	Class 10
Subject	Maths
Chapter	Chapter 13
Chapter Name	Surface Areas and Volumes
Exercise	Ex 13.4
Number of Questions Solved	5
Category	NCERT Solutions

NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.4

NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.4 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.4

Ex 13.4 Class 10 Maths Question 1.
A drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameters of its two circular ends are 4 cm and 2 cm. Find the capacity of the glass.
Solution:

Ex 13.4 Class 10 Maths Question 2.
The slant height of a frustum of a cone is 4 cm and the perimeters (circumference) of its circular ends are 18 cm and 6 cm. Find the curved surface area of the frustum.
Solution:

Download NCERT Solutions For Class 10 Maths Chapter 13 Surface Areas and Volumes PDF

Ex 13.4 Class 10 Maths Question 3.
A fez, the cap used by the Turks, is shaped like the frustum of a cone. If its radius on the open side is 10 cm, radius at the upper base is 4 cm and its slant height is 15 cm, find the area of material used for making it.

Solution:

Ex 13.4 Class 10 Maths Question 4.
A container, opened from the top and made up of a metal sheet, is in the form of a frustum of a cone of height 16 cm with radii of its lower and upper ends as 8 cm and 20 cm, respectively. Find the cost of the milk which can completely fill the container, at the rate of Rs 20 per litre. Also find the cost of metal sheet used to make the container, if it costs Rs 8 per 100 cm2.
Solution:

Ex 13.4 Class 10 Maths Question 5.
A metallic right circular cone 20 cm high and whose vertical angle is 60 is cut into two parts at the middle of its height by a plane parallel to its base. If the frustum so obtained be drawn into a wire of diameter 1/16 cm, find the length of the wire.
Solution:

NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes (Hindi Medium) Ex 13.4

We hope the NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.4, help you. If you have any query regarding NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Exercise 13.4, drop a comment below and we will get back to you at the earliest.

Get Free NCERT Solutions for Class 10 Maths Chapter 5 Ex 5.3 PDF. Arithmetic Progressions Class 10 Maths NCERT Solutions are extremely helpful while doing your homework. Exercise 5.3 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 5 Maths Class 10 Arithmetic Progressions Exercise 5.3 provided in NCERT TextBook.

Topics and Sub Topics in Class 10 Maths Chapter 5 Arithmetic Progressions:

Section Name	Topic Name
5	Arithmetic Progressions
5.1	Introduction
5.2	Arithmetic Progressions
5.3	Nth Term Of An AP
5.4	Sum Of First N Terms Of An AP
5.5	Summary

• Class 10 Maths Arithmetic Progressions Ex 5.1
• प्रश्नावली 5.1 का हल हिंदी में
• Class 10 Maths Arithmetic Progressions Ex 5.2
• प्रश्नावली 5.2 का हल हिंदी में
• Class 10 Maths Arithmetic Progressions Ex 5.3
• प्रश्नावली 5.3 का हल हिंदी में
• Class 10 Maths Arithmetic Progressions Ex 5.4
• प्रश्नावली 5.4 का हल हिंदी में
• Arithmetic Progressions Class 10 Extra Questions

You can also download the free PDF of  Ex 5.3 Class 10 Arithmetic Progressions NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

Board	CBSE
Textbook	NCERT
Class	Class 10
Subject	Maths
Chapter	5
Chapter Name	Arithmetic Progressions
Exercise	Ex 5.3
Number of Questions Solved	20
Category	NCERT Solutions

NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Ex 5.3

NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Ex 5.3 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Exercise 5.3

Ex 5.3 Class 10 Maths Question 1.
Find the sum of the following APs:
(i) 2, 7, 12,…… to 10 terms.
(ii) -37, -33, -29, …… to 12 terms.
(iii) 0.6, 1.7, 2.8, ……, to 100 terms.
(iv) \(\frac { 1 }{ 15 }\), \(\frac { 1 }{ 12 }\), \(\frac { 1 }{ 10 }\), …….., to 11 terms.
Solution:

Ex 5.3 Class 10 Maths Question 2.
Find the sums given below:
(i) 7 + 10\(\frac { 1 }{ 2 }\) + 14 + … + 84
(ii) 34 + 32 + 30 + … + 10
(iii) -5 + (-8) + (-11) + ….. + (-230)
Solution:

Download NCERT Solutions For Class 10 Maths Chapter 5 Arithmetic Progressions PDF

Ex 5.3 Class 10 Maths Question 3.
In an AP:
(i) given a = 5, d = 3, a_n = 50, find n and S_n.
(ii) given a = 7, a₁₃ = 35, find d and S₁₃.
(iii) given a₁₂ = 37, d = 3, find a and S₁₂.
(iv) given a₃ = -15, S₁₀ = 125, find d and a₁₀.
(v) given d = 5, S₉ = 75, find a and a₉.
(vi) given a = 2, d = 8, S_n = 90, find n and a_n.
(vii) given a = 8, a_n = 62, S_n = 210, find n and d.
(viii) given a_n = 4, d = 2, S_n = -14, find n and a.
(ix) given a = 3, n = 8, S = 192, find d.
(x) given l = 28, S = 144, and there are total 9 terms. Find a.
Solution:

Ex 5.3 Class 10 Maths Question 4.
How many terms of AP: 9, 17, 25, … must be taken to give a sum of 636?
Solution:

Ex 5.3 Class 10 Maths Question 5.
The first term of an AP is 5, the last term is 45 and the sum is 400. Find the number of terms and the common difference.
Solution:

Ex 5.3 Class 10 Maths Question 6.
The first and the last terms of an AP are 17 and 350 respectively. If the common difference is 9, how many terms are there and what is their sum?
Solution:

Ex 5.3 Class 10 Maths Question 7.
Find the sum of first 22 terms of an AP in which d = 7 and 22nd term is 149.
Solution:

Ex 5.3 Class 10 Maths Question 8.
Find the sum of first 51 terms of an AP whose second and third terms are 14 and 18 respectively.
Solution:

Ex 5.3 Class 10 Maths Question 9.
If the sum of first 7 terms of an AP is 49 and that of 17 terms is 289, find the sum of first n terms.
Solution:

Ex 5.3 Class 10 Maths Question 10.
Show that a₁, a₂, ……. a_n,…… form an AP where an is defined as below:
(i) a_n = 3 + 4n
(ii) a_n = 9 – 5n
Also find the sum of the first 15 terms in each case.
Solution:

Ex 5.3 Class 10 Maths Question 11.
If the sum of the first n terms of an AP is 4n – n², what is the first term (that is S₁)? What is the sum of first two terms? What is the second term? Similarly, find the 3rd, the 10th and the nth terms.
Solution:

Ex 5.3 Class 10 Maths Question 12.
Find the sum of the first 40 positive integers divisible by 6.
Solution:

Ex 5.3 Class 10 Maths Question 13.
Find the sum of the first 15 multiples of 8.
Solution:

Ex 5.3 Class 10 Maths Question 14.
Find the sum of the odd numbers between 0 and 50.
Solution:

Ex 5.3 Class 10 Maths Question 15.
A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows:
₹ 200 for the first day, ₹ 250 for the second day, ₹ 300 for the third day, etc. the penalty for each succeeding day being ₹ 50 more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by 30 days?
Solution:

Ex 5.3 Class 10 Maths Question 16.
A sum of ₹ 700 is to be used to give seven cash prizes to students of a school for their overall academic performance. If each prize is ₹ 20 less than its preceding prize, find the value of each of the prizes.
Solution:

Ex 5.3 Class 10 Maths Question 17.
In a school, students thought of planting trees in and around the school to reduce air pollution. It was decided that the number of trees, that each section of each class will plant, will be the same as the class, in which they are studying, eg. a section of Class I will plant 1 tree, a section of Class II will plant 2 trees and so on till Class XII. There are three sections of each class. How many trees will be planted by the students?
Solution:

Ex 5.3 Class 10 Maths Question 18.
A spiral is made up of successive semicircles, with centres alternately at A and B, starting with centre at A, of radii 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm,… as shown in figure. What is the total length of such a spiral made up of thirteen consecutive semicircles?
(Take π = \(\frac { 22 }{ 7 }\))
[Hint: Length of successive semicircles is l₁, l₂, l₃, l₄, … with centres at A, B, respectively.]

Solution:

Ex 5.3 Class 10 Maths Question 19.
200 logs are stacked in the following manner 20 logs in the bottom row, 19 in the next row, 18 in the row next to it and so on (see Figure). In how many rows are the 200 logs placed and how many logs are in the top row?

Solution:

Ex 5.3 Class 10 Maths Question 20.
In a potato race, a bucket is placed at the starting point, which is 5 m from the first potato, and the other potatoes are placed 3 m apart in a straight line. There are ten potatoes in the line

A competitor starts from the bucket, picks up the nearest potato, runs back with it, drops it in the bucket, runs back to pick up the next potato, runs to the bucket to drop it in, and she continues in the same way until all the potatoes are in the bucket. What is the total distance the competitor has to run?
Solution:

CLASS 10 MATHS CHAPTER 5 EXERCISE 5.3 AP SOLUTIONS IN HINDI

We hope the NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Ex 5.3, help you. If you have any query regarding NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Exercise 5.3, drop a comment below and we will get back to you at the earliest.