NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.4

Get Free NCERT Solutions for Class 10 Maths Chapter 13 Ex 13.4 PDF. Surface Areas and Volumes Class 10 Maths NCERT Solutions are extremely helpful while doing your homework. Exercise 13.4 Class 10 Maths NCERT Solutions were prepared by Experienced LearnCBSE.in Teachers. Detailed answers of all the questions in Chapter 13 Maths Class 10 Surface Areas and Volumes Exercise 13.4 provided in NCERT TextBook.

Topics and Sub Topics in Class 10 Maths Chapter 13 Surface Areas and Volumes:

Section Name	Topic Name
13	Surface Areas And Volumes
13.1	Introduction
13.2	Surface Area Of A Combination Of Solids
13.3	Volume Of A Combination Of Solids
13.4	Conversion Of Solid From One Shape To Another
13.5	Frustum Of A Cone
13.6	Summary

• Surface Areas and Volumes Class 10 Ex 13.1
• प्रश्नावली 13.1 का हल हिंदी में
• Surface Areas and Volumes Class 10 Ex 13.2
• प्रश्नावली 13.2 का हल हिंदी में
• Surface Areas and Volumes Class 10 Ex 13.3
• प्रश्नावली 13.3 का हल हिंदी में
• Surface Areas and Volumes Class 10 Ex 13.4
• प्रश्नावली 13.4 का हल हिंदी में
• Surface Areas and Volumes Class 10 Ex 13.5
• प्रश्नावली 13.5 का हल हिंदी में
• Surface Areas and Volumes Class 10 Extra Questions

You can also download the free PDF of  Ex 13.4 Class 10 Surface Areas and Volumes NCERT Solutions or save the solution images and take the print out to keep it handy for your exam preparation.

Board	CBSE
Textbook	NCERT
Class	Class 10
Subject	Maths
Chapter	Chapter 13
Chapter Name	Surface Areas and Volumes
Exercise	Ex 13.4
Number of Questions Solved	5
Category	NCERT Solutions

NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.4

NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.4 are part of NCERT Solutions for Class 10 Maths. Here we have given NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes Ex 13.4

Ex 13.4 Class 10 Maths Question 1.
A drinking glass is in the shape of a frustum of a cone of height 14 cm. The diameters of its two circular ends are 4 cm and 2 cm. Find the capacity of the glass.
Solution:

Ex 13.4 Class 10 Maths Question 2.
The slant height of a frustum of a cone is 4 cm and the perimeters (circumference) of its circular ends are 18 cm and 6 cm. Find the curved surface area of the frustum.
Solution:

Download NCERT Solutions For Class 10 Maths Chapter 13 Surface Areas and Volumes PDF

Ex 13.4 Class 10 Maths Question 3.
A fez, the cap used by the Turks, is shaped like the frustum of a cone. If its radius on the open side is 10 cm, radius at the upper base is 4 cm and its slant height is 15 cm, find the area of material used for making it.

Solution:

Ex 13.4 Class 10 Maths Question 4.
A container, opened from the top and made up of a metal sheet, is in the form of a frustum of a cone of height 16 cm with radii of its lower and upper ends as 8 cm and 20 cm, respectively. Find the cost of the milk which can completely fill the container, at the rate of Rs 20 per litre. Also find the cost of metal sheet used to make the container, if it costs Rs 8 per 100 cm2.
Solution:

Ex 13.4 Class 10 Maths Question 5.
A metallic right circular cone 20 cm high and whose vertical angle is 60 is cut into two parts at the middle of its height by a plane parallel to its base. If the frustum so obtained be drawn into a wire of diameter 1/16 cm, find the length of the wire.
Solution:

NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volumes (Hindi Medium) Ex 13.4

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