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NCERT Solutions for Class 11 Maths Chapter 4 Principle of Mathematical Induction
Topics and Sub Topics in Class 11 Maths Chapter 4 Principle of Mathematical Induction:
Section Name | Topic Name |
4 | Principle of Mathematical Induction |
4.1 | Introduction |
4.2 | Motivation |
4.3 | The Principle of Mathematical Induction |
NCERT Solutions for Class 11 Maths Chapter 4 Exercise 4.1
Ex 4.1 Class 11 Maths Question 1:
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Ex 4.1 Class 11 Maths Question 2:
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NCERT Solutions For Class 11 Maths(Download PDF)
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Prove the following through the principle of mathematical induction for all values of n, where n is a natural number.
1) 1+3+3²+….+3n-1=\(\frac { { (3 }^{ n }-1) }{ 2 } \)
2: 1³+2³+3³+……+n³ = \({ (\frac { n(n+1) }{ 2 } ) }^{ 2 }\)
3: \(1+\frac { 1 }{ 1+2 } +\frac { 1 }{ 1+2+3 } +……+\frac { 1 }{ 1+2+3+…+n } =\frac { 2n }{ n+1 } \)
4: 1.2.3+2.3.4+…+n(n+1)(n+2)= \(\frac { n(n+1)(n+2)(n+3) }{ 4 } \)
5: 1.3+2.32+3.33+…+n.3n
NCERT Solutions for Class 11 Maths Chapter 4 Principle of Mathematical Induction Hindi medium Ex 4.1
NCERT Solutions for Class 11 Maths All Chapters
- Chapter 1 Sets
- Chapter 2 Relations and Functions
- Chapter 3 Trigonometric Functions
- Chapter 4 Principle of Mathematical Induction
- Chapter 5 Complex Numbers and Quadratic Equations
- Chapter 6 Linear Inequalities
- Chapter 7 Permutation and Combinations
- Chapter 8 Binomial Theorem
- Chapter 9 Sequences and Series
- Chapter 10 Straight Lines
- Chapter 11 Conic Sections
- Chapter 12 Introduction to Three Dimensional Geometry
- Chapter 13 Limits and Derivatives
- Chapter 14 Mathematical Reasoning
- Chapter 15 Statistics
- Chapter 16 Probability