{"id":95387,"date":"2019-10-04T10:57:28","date_gmt":"2019-10-04T05:27:28","guid":{"rendered":"https:\/\/www.cbselabs.com\/?p=95387"},"modified":"2021-09-18T15:16:37","modified_gmt":"2021-09-18T09:46:37","slug":"ncert-solutions-for-class-8-maths-chapter-7-cubes-and-cube-roots","status":"publish","type":"post","link":"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-8-maths-chapter-7-cubes-and-cube-roots\/","title":{"rendered":"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots"},"content":{"rendered":"<h2>NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots<\/h2>\n<ul>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-8-maths-chapter-7-cubes-and-cube-roots\/\" target=\"_blank\" rel=\"noopener noreferrer\">Class 8 Maths Cubes and Cube Roots Exercise 7.1<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-8-maths-cubes-and-cube-roots-ex-7-2\/\">Class 8 Maths Cubes and Cube Roots Exercise 7.2<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/cubes-and-cube-roots-ncert-extra-questions-for-class-8-maths\/\">Cubes and Cube Roots Class 8 Extra Questions<\/a><\/li>\n<\/ul>\n<p><strong>NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Exercise 7.1<\/strong><\/p>\n<p>Ex 7.1 Class 8 Maths Question 1.<br \/>\nWhich of the following numbers are not perfect cubes?<br \/>\n(i) 216<br \/>\n(ii) 128<br \/>\n(iii) 1000<br \/>\n(iv) 100<br \/>\n(v) 46656<br \/>\nSolution:<br \/>\n(i) Prime factorisation of 216 is:<br \/>\n216 = <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 <span style=\"text-decoration: underline;\">3 \u00d7 3 \u00d7 3<\/span><br \/>\nIn the above factorisation, 2 and 3 have formed a group of three.<br \/>\nThus, 216 is a perfect cube.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106233\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q1.png?resize=101%2C165&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q1\" width=\"101\" height=\"165\" data-recalc-dims=\"1\" \/><br \/>\n(ii) Prime factorisation of 128 is:<br \/>\n128 = <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 2<br \/>\nHere, 2 is left without making a group of three.<br \/>\nThus 128 is not a perfect cube.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106229\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q1.1.png?resize=95%2C190&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q1.1\" width=\"95\" height=\"190\" data-recalc-dims=\"1\" \/><br \/>\n(iii) Prime factorisation of 1000, is:<br \/>\n1000 = <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 <span style=\"text-decoration: underline;\">5 \u00d7 5 \u00d7 5<\/span><br \/>\nHere, no number is left for making a group of three.<br \/>\nThus, 1000 is a perfect cube.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106230\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q1.2.png?resize=100%2C168&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q1.2\" width=\"100\" height=\"168\" data-recalc-dims=\"1\" \/><br \/>\n(iv) Prime factorisation of 100, is:<br \/>\n100 = <span style=\"text-decoration: underline;\">2 \u00d7 2<\/span> \u00d7 <span style=\"text-decoration: underline;\">5 \u00d7 5<\/span><br \/>\nHere 2 and 5 have not formed a group of three.<br \/>\nThus, 100 is not a perfect cube.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106231\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q1.3.png?resize=91%2C124&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q1.3\" width=\"91\" height=\"124\" data-recalc-dims=\"1\" \/><br \/>\n(v) Prime factorisation of 46656 is:<br \/>\n46656 = <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 <span style=\"text-decoration: underline;\">3 \u00d7 3 \u00d7 3<\/span> \u00d7 <span style=\"text-decoration: underline;\">3 \u00d7 3 \u00d7 3<\/span><br \/>\nHere 2 and 3 have formed the groups of three.<br \/>\nThus, 46656 is a perfect cube.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106232\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q1.4.png?resize=116%2C303&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q1.4\" width=\"116\" height=\"303\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q1.4.png?w=116&amp;ssl=1 116w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q1.4.png?resize=115%2C300&amp;ssl=1 115w\" sizes=\"(max-width: 116px) 100vw, 116px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Ex 7.1 Class 8 Maths\u00a0Question 2.<br \/>\nFind the smallest number by which each of the following numbers must be multiplied to obtain a perfect cube.<br \/>\n(i) 243<br \/>\n(ii) 256<br \/>\n(iii) 72<br \/>\n(iv) 675<br \/>\n(v) 100<br \/>\nSolution:<br \/>\n(i) Prime factorisation of 243, is:<br \/>\n243 = <span style=\"text-decoration: underline;\">3 \u00d7 3 \u00d7 3<\/span> \u00d7 3 \u00d7 3 = 3<sup>3<\/sup> \u00d7 3 \u00d7 3<br \/>\nHere, number 3 is required to make 3 \u00d7 3 a group of three, i.e., 3 \u00d7 3 \u00d7 3<br \/>\nThus, the required smallest number to be multiplied is 3.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106239\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q2.png?resize=102%2C151&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q2\" width=\"102\" height=\"151\" data-recalc-dims=\"1\" \/><br \/>\n(ii) Prime factorisation of 256, is:<br \/>\n256 = <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 2 \u00d7 2 = 2<sup>3<\/sup> \u00d7 2<sup>3<\/sup> \u00d7 2 \u00d7 2<br \/>\nHere, a number 2 is needed to make 2 \u00d7 2 a group of three, i.e., 2 \u00d7 2 \u00d7 2<br \/>\nThus, the required smallest number to be multiplied is 2.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106235\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q2.1.png?resize=98%2C211&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q2.1\" width=\"98\" height=\"211\" data-recalc-dims=\"1\" \/><br \/>\n(iii) Prime factorisation of 72, is:<br \/>\n72 = <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 3 \u00d7 3 = 2<sup>3<\/sup> \u00d7 3 \u00d7 3<br \/>\nHere, a number 3 is required to make 3 \u00d7 3 a group of three, i.e. 3 \u00d7 3 \u00d7 3<br \/>\nThus, the required smallest number to be multiplied is 3.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106236\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q2.2.png?resize=97%2C140&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q2.2\" width=\"97\" height=\"140\" data-recalc-dims=\"1\" \/><br \/>\n(iv) Prime factorisation of 675, is:<br \/>\n675 = <span style=\"text-decoration: underline;\">3 \u00d7 3 \u00d7 3<\/span> \u00d7 5 \u00d7 5 = 3<sup>3<\/sup> \u00d7 5 \u00d7 5<br \/>\nHere, a number 5 is required to make 5 \u00d7 5 a group of three to make it a perfect cube, i.e. 5 \u00d7 5 \u00d7 5<br \/>\nThus, the required smallest number is 5.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106237\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q2.3.png?resize=96%2C144&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q2.3\" width=\"96\" height=\"144\" data-recalc-dims=\"1\" \/><br \/>\n(v) Prime factorisation of 100, is:<br \/>\n100 = 2 \u00d7 2 \u00d7 5 \u00d7 5<br \/>\nHere, number 2 and 5 are needed to multiplied 2 \u00d7 2 \u00d7 5 \u00d7 5 to make it a perfect cube, i.e., 2 \u00d7 2 \u00d7 2 \u00d7 5 \u00d7 5 \u00d7 5<br \/>\nThus, the required smallest number to be multiplied is 2 \u00d7 5 = 10.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106238\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q2.4.png?resize=96%2C120&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q2.4\" width=\"96\" height=\"120\" data-recalc-dims=\"1\" \/><\/p>\n<p>Ex 7.1 Class 8 Maths\u00a0Question 3.<br \/>\nFind the smallest number by which each of the following numbers must be divided to obtain a perfect cube.<br \/>\n(i) 81<br \/>\n(ii) 128<br \/>\n(iii) 135<br \/>\n(iv) 92<br \/>\n(v) 704<br \/>\nSolution:<br \/>\n(i) Prime factorisation of 81, is:<br \/>\n81 = <span style=\"text-decoration: underline;\">3 \u00d7 3 \u00d7 3<\/span> \u00d7 3 = 3<sup>3<\/sup> \u00d7 3<br \/>\nHere, a number 3 is the number by which 81 is divided to make it a perfect cube,<br \/>\ni.e., 81 \u00f7 3 = 27 which is a perfect cube.<br \/>\nThus, the required smallest number to be divided is 3.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106244\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q3.png?resize=84%2C122&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q3\" width=\"84\" height=\"122\" data-recalc-dims=\"1\" \/><br \/>\n(ii) Prime factorisation of 128, is:<br \/>\n128 = <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 2 = 2<sup>3<\/sup> \u00d7 2<sup>3<\/sup> \u00d7 2<br \/>\nHere, a number 2 is the smallest number by which 128 is divided to make it a perfect cube,<br \/>\ni.e., 128 \u00f7 2 = 64 which is a perfect cube.<br \/>\nThus, 2 is the required smallest number.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106240\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q3.1.png?resize=93%2C188&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q3.1\" width=\"93\" height=\"188\" data-recalc-dims=\"1\" \/><br \/>\n(iii) Prime factorisation of 135 is:<br \/>\n135 = <span style=\"text-decoration: underline;\">3 \u00d7 3 \u00d7 3<\/span> \u00d7 5 = 3<sup>3<\/sup> \u00d7 5<br \/>\nHere, 5 is the smallest number by which 135 is divided to make a perfect cube,<br \/>\ni.e., 135 \u00f7 5 = 27 which is a perfect cube.<br \/>\nThus, 5 is the required smallest number.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106241\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q3.2.png?resize=81%2C127&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q3.2\" width=\"81\" height=\"127\" data-recalc-dims=\"1\" \/><br \/>\n(iv) Prime factorisation of 192 is:<br \/>\n192 = <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 3 = 2<sup>3<\/sup> \u00d7 2<sup>3<\/sup> \u00d7 3<br \/>\nHere, 3 is the smallest number by which 192 is divided to make it a perfect cube,<br \/>\ni.e., 192 \u00f7 3 = 64 which is a perfect cube.<br \/>\nThus, 3 is the required smallest number.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106242\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q3.3.png?resize=95%2C193&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q3.3\" width=\"95\" height=\"193\" data-recalc-dims=\"1\" \/><br \/>\n(v) Prime factorisation of 704 is:<br \/>\n704 = <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 <span style=\"text-decoration: underline;\">2 \u00d7 2 \u00d7 2<\/span> \u00d7 11 = 2<sup>3<\/sup> \u00d7 2<sup>3<\/sup> \u00d7 11<br \/>\nHere, 11 is the smallest number by which 704 is divided to make it a perfect cube,<br \/>\ni.e., 704 \u00f7 11 = 64 which is a perfect cube.<br \/>\nThus, 11 is the required smallest number.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-106243\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-Q3.4.png?resize=104%2C189&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 Q3.4\" width=\"104\" height=\"189\" data-recalc-dims=\"1\" \/><\/p>\n<p>Ex 7.1 Class 8 Maths\u00a0Question 4.<br \/>\nParikshit makes a cuboid of plasticine of sides 5 cm, 2 cm, 5 cm. How many such cuboids will be needed to form a cube?<br \/>\nSolution:<br \/>\nThe sides of the cuboid are given as 5 cm, 2 cm and 5 cm.<br \/>\nVolume of the cuboid = 5 cm \u00d7 2 cm \u00d7 5 cm = 50 cm<sup>3<\/sup><br \/>\nFor the prime factorisation of 50, we have<br \/>\n50 = 2 \u00d7 5 \u00d7 5<br \/>\nTo make it a perfect cube, we must have<br \/>\n2 \u00d7 2 \u00d7 2 \u00d7 5 \u00d7 5 \u00d7 5<br \/>\n= 20 \u00d7 (2 \u00d7 5 \u00d7 5)<br \/>\n= 20 \u00d7 volume of the given cuboid<br \/>\nThus, the required number of cuboids = 20.<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-106234\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.1-q-1.png?resize=720%2C3408&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.1 q-1\" width=\"720\" height=\"3408\" data-recalc-dims=\"1\" \/><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-106245\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-1.png?resize=720%2C3496&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.2 q-1\" width=\"720\" height=\"3496\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-1.png?w=720&amp;ssl=1 720w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-1.png?resize=62%2C300&amp;ssl=1 62w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-1.png?resize=211%2C1024&amp;ssl=1 211w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-1.png?resize=422%2C2048&amp;ssl=1 422w\" sizes=\"(max-width: 720px) 100vw, 720px\" data-recalc-dims=\"1\" \/><\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-106246\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-2.png?resize=720%2C3072&#038;ssl=1\" alt=\"NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Ex 7.2 q-2\" width=\"720\" height=\"3072\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-2.png?w=720&amp;ssl=1 720w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-2.png?resize=70%2C300&amp;ssl=1 70w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-2.png?resize=240%2C1024&amp;ssl=1 240w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-2.png?resize=360%2C1536&amp;ssl=1 360w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/10\/NCERT-Solutions-for-Class-8-Maths-Chapter-7-Cubes-and-Cube-Roots-Ex-7.2-q-2.png?resize=480%2C2048&amp;ssl=1 480w\" sizes=\"(max-width: 720px) 100vw, 720px\" data-recalc-dims=\"1\" \/><\/p>\n<h4>More CBSE Class 8 Study Material<\/h4>\n<ul>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-8-maths\/\">NCERT Solutions for Class 8 Maths<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-8-science\/\">NCERT Solutions for Class 8 Science<\/a><\/li>\n<li><a 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Maths Chapter 7 Cubes and Cube Roots Class 8 Maths Cubes and Cube Roots Exercise 7.1 Class 8 Maths Cubes and Cube Roots Exercise 7.2 Cubes and Cube Roots Class 8 Extra Questions NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots Exercise 7.1 Ex 7.1 Class &hellip;<\/p>\n","protected":false},"author":27,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[2],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v17.2 (Yoast SEO v17.2) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 8 Maths Chapter 7 Cubes and Cube Roots - CBSE Labs<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-8-maths-chapter-7-cubes-and-cube-roots\/\" \/>\n<meta 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