{"id":73948,"date":"2019-09-27T19:00:18","date_gmt":"2019-09-27T13:30:18","guid":{"rendered":"https:\/\/www.cbselabs.com\/?p=73948"},"modified":"2021-09-18T15:17:12","modified_gmt":"2021-09-18T09:47:12","slug":"ncert-solutions-for-class-10-science-chapter-4-carbon-and-its-compounds","status":"publish","type":"post","link":"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-10-science-chapter-4-carbon-and-its-compounds\/","title":{"rendered":"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds"},"content":{"rendered":"<p><strong>NCERT Solutions for Class 10 Science Chapter 4 Carbon And Its Compounds:\u00a0<\/strong>In this article, we will provide you detailed Carbon and Its Compounds Class 10 NCERT Solutions. The\u00a0NCERT Solutions For Class 10 <strong>Science Chapter 4 Carbon And Its Compounds<\/strong> was solved by the best teachers in India to help the students of class 10 to secure good marks in the subject science.<\/p>\n<p><strong>\u00a0<\/strong>NCERT solutions for <strong>class 10 science<\/strong> give a strong foundation for every concept. Working on NCERT solutions will ensure a smooth and clear understanding of all the advanced concepts. According to CBSE marking scheme, <a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-class-10-science\/\">NCERT Solutions For Class 10 Science<\/a> Chapter 4 Carbon And Its Compounds\u00a0will play a major role in competitive exams like JEE, NEET, etc., Read on to find out\u00a0<strong>NCERT Solutions For Class 10 Science Chapter 4<\/strong> Carbon And Its Compounds.<\/p>\n<h2 class=\"entry-title\">NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds<\/h2>\n<p>Before getting into the details of NCERT Solutions for Class 10 Science Chapter 4 Carbon And Its Compounds, let&#8217;s have an overview of a list of units and sub-units under <strong>NCERT Solutions for Class 10 Science Carbon And Its Compounds<\/strong><\/p>\n<ol>\n<li>Carbon And Its Compounds<\/li>\n<li>Bonding In Carbon &#8211; The Covalent Bond<\/li>\n<li>Chemical Properties Of Carbon Compounds<\/li>\n<li>Some Important Carbon Compounds &#8211; Ethanol And Ethanoic Acid<\/li>\n<li>Soaps And Detergents<\/li>\n<\/ol>\n<p>Free download <strong>NCERT Solutions for Class 10 Science Chapter 4 Carbon And Its Compounds PDF<\/strong> in Hindi Medium as well as in English Medium for CBSE, Uttarakhand, Bihar, MP Board, Gujarat Board, and UP Board students, who are using NCERT Books based on updated CBSE Syllabus for the session 2019-20.<\/p>\n<ul>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-10-science-chapter-4-carbon-and-its-compounds\/#Carbon_and_Its_Compounds_Class_10_in_Hindi\">\u0915\u093e\u0930\u094d\u092c\u0928 \u0914\u0930 \u0907\u0938\u0915\u0947 \u092f\u094c\u0917\u093f\u0915 \u0915\u0915\u094d\u0937\u093e 10 \u0935\u093f\u091c\u094d\u091e\u093e\u0928 \u0939\u093f\u0902\u0926\u0940 \u092e\u0947\u0902<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/carbon-and-its-compounds-chapter-wise-important-questions-class-10-science\/\">Class 10 Carbon and its Compounds Important Questions<\/a><\/li>\n<li><a title=\"Carbon and its Compounds Class 10 Notes Science Chapter 4\" href=\"https:\/\/www.cbselabs.com\/carbon-compounds-cbse-notes-class-10-science\/\">Carbon and its Compounds Class 10 Notes<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-exemplar-problems-for-class-10-science-carbon-and-its-compounds\/\">Carbon and its Compounds NCERT Exemplar Solutions<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/extra-questions-carbon-and-its-compounds-cbse-class-10-science\/\">Carbon and Its Compounds Class 10 Extra Questions<\/a><\/li>\n<li><strong style=\"text-align: center;\"><a href=\"#Class_10_Carbon_and_its_Compounds_Mind_Map\">Class 10 Carbon and its Compounds Mind Map<\/a><\/strong><\/li>\n<\/ul>\n<h3>NCERT Solutions for Class 10 Science Chapter 4 Intext Questions<\/h3>\n<p><strong>Page Number: 61<\/strong><\/p>\n<p>Question 1<br \/>\nWhat would be the electron dot structure of carbon dioxide which has the formula CO<sub>2<\/sub> ?<br \/>\nAnswer:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100710\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p61-q1.png?resize=292%2C59&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p61 q1\" width=\"292\" height=\"59\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 2<br \/>\nWhat would be electron dot structure of sulphur which is made up of eight atoms of sulphur.<br \/>\nAnswer:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100711\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p61-q2.png?resize=316%2C207&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p61 q2\" width=\"316\" height=\"207\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p61-q2.png?w=316&amp;ssl=1 316w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p61-q2.png?resize=300%2C197&amp;ssl=1 300w\" sizes=\"(max-width: 316px) 100vw, 316px\" data-recalc-dims=\"1\" \/><\/p>\n<p><strong>Page Number: 68 &#8211; 69<\/strong><\/p>\n<p>Question 1<br \/>\nHow many structural isomers can you draw for pentane ?<br \/>\nAnswer:<br \/>\nThree, these are n-pentane, iso-pentane and neo-pentane.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100712\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q1.png?resize=653%2C216&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p68 q1\" width=\"653\" height=\"216\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q1.png?w=653&amp;ssl=1 653w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q1.png?resize=300%2C99&amp;ssl=1 300w\" sizes=\"(max-width: 653px) 100vw, 653px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 2<br \/>\nWhat are the two properties of carbon which lead to the huge number of carbon compounds we see around us ?<br \/>\nAnswer:<br \/>\n(i) Tetravalency<br \/>\n(ii) Catenation.<\/p>\n<p>Question 3<br \/>\nWhat will be the formula and electron dot structure of cyclopentane ?<br \/>\nAnswer:<br \/>\nThe molecular formula of cyclopentane is C<sub>5<\/sub> H<sub>10<\/sub> .<br \/>\nThe electron dot structure of cyclopentane is given on the next page.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100713\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q3.png?resize=513%2C231&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p68 q3\" width=\"513\" height=\"231\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q3.png?w=513&amp;ssl=1 513w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q3.png?resize=300%2C135&amp;ssl=1 300w\" sizes=\"(max-width: 513px) 100vw, 513px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 4<br \/>\nDraw the structures for the following compounds :<br \/>\n(i) Ethanoic acid<br \/>\n(ii) Bromopentane<br \/>\n(iii) Butanone<br \/>\n(iv) Hexanal<br \/>\nAnswer:<br \/>\n(i) Ethanoic acid (CH<sub>3<\/sub>COOH)<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100714\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q4.png?resize=162%2C96&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p68 q4\" width=\"162\" height=\"96\" data-recalc-dims=\"1\" \/><br \/>\n(ii) Bromopentane (C<sub>5<\/sub>H<sub>11<\/sub>Br)<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100715\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q4a.png?resize=241%2C92&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p68 q4a\" width=\"241\" height=\"92\" data-recalc-dims=\"1\" \/><br \/>\n(iii) Butanone (CH<sub>3<\/sub> \u2014 CH<sub>2<\/sub> \u2014 COCH<sub>3<\/sub>)<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100716\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q4b.png?resize=205%2C95&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p68 q4b\" width=\"205\" height=\"95\" data-recalc-dims=\"1\" \/><br \/>\n(iv) Hexanal (C<sub>5<\/sub>H<sub>11<\/sub>CHO)<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100717\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q4c.png?resize=267%2C95&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p68 q4c\" width=\"267\" height=\"95\" data-recalc-dims=\"1\" \/><\/p>\n<p>Structural isomers for bromopentane: There are three structural isomers for bromopentane depending on the position of Br at carbon 1, 2, 3.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100718\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q4d.png?resize=582%2C232&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p68 q4d\" width=\"582\" height=\"232\" srcset=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q4d.png?w=582&amp;ssl=1 582w, https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q4d.png?resize=300%2C120&amp;ssl=1 300w\" sizes=\"(max-width: 582px) 100vw, 582px\" data-recalc-dims=\"1\" \/><br \/>\nPositions 4 and 5 are same as 1, 2.<\/p>\n<p>Question 5<br \/>\nHow would you name the following compounds ?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100719\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q5.png?resize=414%2C183&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p68 q5\" width=\"414\" height=\"183\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q5.png?w=414&amp;ssl=1 414w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p68-q5.png?resize=300%2C133&amp;ssl=1 300w\" sizes=\"(max-width: 414px) 100vw, 414px\" data-recalc-dims=\"1\" \/><br \/>\nAnswer:<br \/>\n(i) Bromoethane<br \/>\n(ii) Methanal<br \/>\n(iii) 1 &#8211; Hexyne<\/p>\n<p><strong>Page Number: 71<\/strong><\/p>\n<p>Question 1<br \/>\nWhy is the conversion of ethanol to ethanoic acid an oxidation reaction ?<br \/>\nAnswer:<br \/>\nConversion of ethanol into ethanoic acid is an oxidation reaction because addition of oxygen to a substance is called oxidation. Here, oxygen is added to ethanol by oxidising agent like alkaline potassium permanganate or acidified potassium dichromate and it is converted into acid.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100720\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p71-q1.png?resize=439%2C56&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Intext Questions p71 q1\" width=\"439\" height=\"56\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p71-q1.png?w=439&amp;ssl=1 439w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Intext-Questions-p71-q1.png?resize=300%2C38&amp;ssl=1 300w\" sizes=\"(max-width: 439px) 100vw, 439px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 2<br \/>\nA mixture of oxygen and ethyne is burnt for welding. Can you tell why a mixture of ethyne and air is not used ?<br \/>\nAnswer:<br \/>\nA mixture of ethyne and air is not used for welding because burning of ethyne in air produces a sooty flame due to incomplete combustion, which is not enough to melt metals for welding.<\/p>\n<p><strong>Page Number: 74<\/strong><\/p>\n<p>Question 1<br \/>\nHow would you distinguish experimentally between an alcohol and a carboxylic acid ?<br \/>\nAnswer:<br \/>\nDifferences between alcohol and carboxylic acid<\/p>\n<table border=\"2\">\n<tbody>\n<tr>\n<td style=\"text-align: center;\" width=\"156\"><strong>Test<\/strong><\/td>\n<td style=\"text-align: center;\" width=\"168\"><strong>Alcohol<\/strong><\/td>\n<td style=\"text-align: center;\" width=\"212\"><strong>Carboxylic acid<\/strong><\/td>\n<\/tr>\n<tr>\n<td width=\"156\">(i) Litmus test<\/td>\n<td width=\"168\">No change in colour.<\/td>\n<td width=\"212\">Blue litmus solution turns red.<\/td>\n<\/tr>\n<tr>\n<td width=\"156\">(ii) Sodium hydrogen carbonate test<\/td>\n<td width=\"168\">C<sub>2<\/sub>H<sub>5<\/sub>OH + NaHCO<sub>3<\/sub> \u2192 No reaction No brisk effervescence.<\/td>\n<td width=\"212\">CH<sub>3<\/sub>COOH + NaHCO<sub>3 <\/sub>\u2192 CH<sub>3<\/sub>COONa + H<sub>2<\/sub>O + CO<sub>2<\/sub> Brisk effervescence due to evolution of CO<sub>2<\/sub>.<\/td>\n<\/tr>\n<tr>\n<td width=\"156\">(iii) Alkaline potassium permanganate<\/td>\n<td width=\"168\">On heating, pink colour disappears.<\/td>\n<td width=\"212\">Does not happen so.<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Question 2<br \/>\nWhat are oxidising agents ?<br \/>\nAnswer:<br \/>\nOxidising agents are the substances which give oxygen to another substances or which remove hydrogen from a substance.<br \/>\nFor example, acidic K<sub>2<\/sub>Cr<sub>2<\/sub>O<sub>7<\/sub> is an oxidising agent, that converts (oxidises) ethanol into ethanoic acid.<\/p>\n<p><strong>Page Number: 76<\/strong><\/p>\n<p>Question 1<br \/>\nWould you be able to check if water is hard by using a detergent ?<br \/>\nAnswer:<br \/>\nNo, because detergents can lather well even in hard water. They do not form insoluble calcium or magnesium salts (scum). On reacting with the calcium ions and magnesium ions present in the hard water.<\/p>\n<p>Question 2<br \/>\nPeople use a variety of methods to wash clothes. Usually after adding the soap, they \u2018beat\u2019 the clothes on a stone, or beat it with a paddle, scrub with a brush or the mixture is agitated in a washing machine. Why is agitation necessary to get clean clothes ?<br \/>\nAnswer:<br \/>\nIt is necessary to agitate to get clean clothes because the soap micelles which entrap oily or greasy particles on the surface of dirty cloth have to be removed from its surface. When the cloth wetted in soap solution is agitated or beaten, the micelles containing oily or greasy dirt get removed from the surface of dirty cloth and go into water and the dirty cloth gets cleaned.<\/p>\n<h3>NCERT Solutions for Class 10 Science Chapter 4 Textbook Chapter End Questions<\/h3>\n<p>Question 1<br \/>\nEthane, with the molecular formula C<sub>2<\/sub>H<sub>6 <\/sub>has<br \/>\n(a) 6 covalent bonds<br \/>\n(b) 7 covalent bonds<br \/>\n(c) 8 covalent bonds<br \/>\n(d) 9 covalent bonds<br \/>\nAnswer:<br \/>\n(b) 7 covalent bonds.<\/p>\n<p>Question 2<br \/>\nButanone is a four-carbon compound with the functional group<br \/>\n(a) carboxylic acid<br \/>\n(b) aldehyde<br \/>\n(c) ketone<br \/>\n(d) alcohol<br \/>\nAnswer:<br \/>\n(c) Ketone.<\/p>\n<p>Question 3<br \/>\nWhile cooking, if the bottom of the vessel is getting blackened on the outside, it means that<br \/>\n(a) the food is not cooked completely.<br \/>\n(b) the fuel is not burning completely.<br \/>\n(c) the fuel is wet.<br \/>\n(d) the fuel is burning completely.<br \/>\nAnswer:<br \/>\n(b) The fuel is not burning completely.<\/p>\n<p>Question 4<br \/>\nExplain the nature of the covalent bond using the bond formation in CH<sub>3<\/sub>Cl.<br \/>\nAnswer:<br \/>\nCovalent bond is formed by sharing of electrons so that the combining atoms complete their outermost shell.<\/p>\n<p>In CH<sub>3<\/sub>Cl : C = 6, H = 1 and Cl = 17 And their electronic configuration is C &#8211; 2,4, H &#8211; 1 and Cl &#8211; 2, 8, 7<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100721\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Textbook-Chapter-End-Questions-Q4.png?resize=326%2C154&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Textbook Chapter End Questions Q4\" width=\"326\" height=\"154\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Textbook-Chapter-End-Questions-Q4.png?w=326&amp;ssl=1 326w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Textbook-Chapter-End-Questions-Q4.png?resize=300%2C142&amp;ssl=1 300w\" sizes=\"(max-width: 326px) 100vw, 326px\" data-recalc-dims=\"1\" \/><br \/>\nThree hydrogen atoms complete their shells by sharing three electrons (one electron each) of carbon atom.<br \/>\nChlorine completes its outer shell by sharing its one out of seven electrons with one electron of carbon atom.<br \/>\nThus carbon atom shares all its four electrons with three hydrogen atoms and one of chlorine atom and completes its outermost shell and single covalent bonds are formed in CH<sub>3<\/sub>Cl.<\/p>\n<p>Question 5<br \/>\nDraw the electron dot structures for<br \/>\n(a) ethanoic acid<br \/>\n(b) propanone<br \/>\n(c) H<sub>2<\/sub>S<br \/>\n(d) F<sub>2<\/sub>.<br \/>\nAnswer:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100722\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Textbook-Chapter-End-Questions-Q5.png?resize=625%2C389&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Textbook Chapter End Questions Q5\" width=\"625\" height=\"389\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Textbook-Chapter-End-Questions-Q5.png?w=625&amp;ssl=1 625w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Textbook-Chapter-End-Questions-Q5.png?resize=300%2C187&amp;ssl=1 300w\" sizes=\"(max-width: 625px) 100vw, 625px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 6<br \/>\nWhat is a homologous series ? Explain with an example.<br \/>\nAnswer:<br \/>\nHomologous series : A homologous series is a group of organic compounds having<br \/>\nsimilar structures and similar chemical properties in which the successive compounds differ by -CH<sub>2<\/sub> group.<\/p>\n<p><strong>Characteristics of homologous series :<\/strong><br \/>\n(i) All members of a homologous series can be represented by the same general formula. For example, the general formula of the homologous series of alkanes is C<sub>n<\/sub>H<sub>2n+2<\/sub>, in which \u2018n\u2019 denotes number of carbon and hydrogen atoms in one molecule of alkane.<br \/>\n(ii) Any two adjacent homologues differ by one carbon atom and two hydrogen atoms in their molecular formulae.<br \/>\n(iii) The difference in the molecular masses of any two adjacent homologues is 14u.<br \/>\n(iv) All the compounds of a homologous series show similar chemical properties.<br \/>\n(v) The members of a homologous series show a gradual change in their physical properties with increase in molecular mass.<\/p>\n<p>For example, general formula of the homologous series of alkanes is C<sub>n<\/sub>H<sub>2n+2<\/sub>, in which \u2018n\u2019 denotes number of carbon atoms in one molecule of alkane. Following are the first five members of the homologous series of alkanes (general formula C<sub>n<\/sub>H<sub>2n+2<\/sub>).<\/p>\n<table border=\"2\">\n<tbody>\n<tr>\n<td style=\"text-align: center;\" width=\"97\"><strong>Value of n<\/strong><\/td>\n<td style=\"text-align: center;\" width=\"142\"><strong>Molecular formula<\/strong><\/td>\n<td style=\"text-align: center;\" width=\"159\"><strong>Name of compound<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"97\">1<\/td>\n<td style=\"text-align: center;\" width=\"142\">CH<sub>4<\/sub><\/td>\n<td style=\"text-align: center;\" width=\"159\">Methane<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"97\">2<\/td>\n<td style=\"text-align: center;\" width=\"142\">C<sub>2<\/sub>H<sub>6<\/sub><\/td>\n<td style=\"text-align: center;\" width=\"159\">Ethane<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"97\">3<\/td>\n<td style=\"text-align: center;\" width=\"142\">C<sub>3<\/sub>H<sub>8<\/sub><\/td>\n<td style=\"text-align: center;\" width=\"159\">Propane<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"97\">4<\/td>\n<td style=\"text-align: center;\" width=\"142\">C<sub>4<\/sub>H<sub>10<\/sub><\/td>\n<td style=\"text-align: center;\" width=\"159\">Butane<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"97\">5<\/td>\n<td style=\"text-align: center;\" width=\"142\">C<sub>5<\/sub>H<sub>12<\/sub><\/td>\n<td style=\"text-align: center;\" width=\"159\">Pentane<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Question 7<br \/>\nHow can ethanol and ethanoic acid he differentiated on the basis of their physical and chemical properties ?<br \/>\nAnswer:<br \/>\nDifference on the basis of physical properties<\/p>\n<table border=\"2\">\n<tbody>\n<tr>\n<td style=\"text-align: center;\" width=\"145\"><strong>Property<\/strong><\/td>\n<td style=\"text-align: center;\" width=\"100\"><strong>Ethanol<\/strong><\/td>\n<td style=\"text-align: center;\" width=\"190\"><strong>Ethanoic acid<\/strong><\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: left;\" width=\"145\">(i) State<\/td>\n<td style=\"text-align: left;\" width=\"100\">Liquid<\/td>\n<td style=\"text-align: left;\" width=\"190\">Liquid<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: left;\" width=\"145\">(ii) Odour<\/td>\n<td style=\"text-align: left;\" width=\"100\">Sweet smell<\/td>\n<td style=\"text-align: left;\" width=\"190\">Pungent vinegar-like smell<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: left;\" width=\"145\">(iii) Melting point<\/td>\n<td style=\"text-align: left;\" width=\"100\">156 K<\/td>\n<td style=\"text-align: left;\" width=\"190\">290 K<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: left;\" width=\"145\">(iv) Boiling point<\/td>\n<td style=\"text-align: left;\" width=\"100\">351 K<\/td>\n<td style=\"text-align: left;\" width=\"190\">391 K<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Difference on the basis of chemical properties<\/p>\n<table border=\"2\">\n<tbody>\n<tr>\n<td style=\"text-align: center;\" width=\"158\"><strong>Test<\/strong><\/td>\n<td style=\"text-align: center;\" width=\"163\"><strong>Ethanol<\/strong><\/td>\n<td style=\"text-align: center;\" width=\"214\"><strong>Ethanoic acid<\/strong><\/td>\n<\/tr>\n<tr>\n<td width=\"158\">(i) Litmus test<\/td>\n<td width=\"163\">No change in the colour of litmus solution.<\/td>\n<td width=\"214\">Blue litmus solution turns red.<\/td>\n<\/tr>\n<tr>\n<td width=\"158\">(ii) Sodium hydrogen carbonate test<\/td>\n<td width=\"163\">C<sub>2<\/sub>H<sub>5<\/sub>OH + NaHCO<sub>3 <\/sub>\u2192 No reaction No brisk effervescence.<\/td>\n<td width=\"214\">CH<sub>3<\/sub>COOH + NaHCO<sub>3<\/sub> \u2192 CH<sub>3<\/sub>COONa + H<sub>2<\/sub>O + CO<sub>2 <\/sub>Brisk effervescence due to evolution of CO<sub>2<\/sub>.<\/td>\n<\/tr>\n<tr>\n<td width=\"158\">(iii) Alkaline potassium permanganate<\/td>\n<td width=\"163\">On heating, pink colour disappears.<\/td>\n<td width=\"214\">Does not happen so.<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>Question 8<br \/>\nWhy does micelle formation take place when soap is added to water ? Will a micell be formed in other solvents such as ethanol also ?<br \/>\nAnswer:<br \/>\nMicelle formation takes place when soap is added to water because the hydrocarbon chains of soap molecules are hydrophobic (water repelling) which are insoluble in water, but the ionic ends of soap molecules are hydrophilic (water attracting) and hence soluble in water.<br \/>\nSuch micelle formation will not be possible in other solvents like ethanol in which sodium salt of fatty acids do not dissolve.<\/p>\n<p>Question 9<br \/>\nWhy are carbon and its compounds used as fuels for most applications ?<br \/>\nAnswer:<br \/>\nCarbon and its compounds give a large amount of heat per unit weight and are therefore, used as fuels for most applications.<\/p>\n<p>Question 10<br \/>\nExplain the formation of scum when hard water is treated with soap.<br \/>\nAnswer:<br \/>\nHard water contains salts of calcium and magnesium. Calcium and magnesium on reacting with soap form insoluble precipitate called scum. The scum formation lessens the cleansing property of soaps in hard water.<\/p>\n<p>Question 11<br \/>\nWhat change will you observe if you test soap with litmus paper (red and blue)?<br \/>\nAnswer:<br \/>\nRed litmus will turn blue because soap is alkaline in nature. Blue litmus remains blue in soap solution.<\/p>\n<p>Question 12<br \/>\nWhat is hydrogenation ? What is its industrial application ?<br \/>\nAnswer:<br \/>\nThe addition of hydrogen to an unsaturated hydrocarbon to obtain a saturated hydro-carbon is called hydrogenation. The process of hydrogenation takes place in the presence of nickel (Ni) or palladium (Pd) metals as catalyst.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100723\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Textbook-Chapter-End-Questions-Q12.png?resize=484%2C110&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Textbook Chapter End Questions Q12\" width=\"484\" height=\"110\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Textbook-Chapter-End-Questions-Q12.png?w=484&amp;ssl=1 484w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Textbook-Chapter-End-Questions-Q12.png?resize=300%2C68&amp;ssl=1 300w\" sizes=\"(max-width: 484px) 100vw, 484px\" data-recalc-dims=\"1\" \/><br \/>\nApplication : The process of hydrogenation has an important industrial application. It is used to prepare vegetable ghee (or vanaspati ghee) from vegetable oils.<\/p>\n<p>Question 13<br \/>\nWhich of the following hydrocarbons undergo addition reactions :<br \/>\nC<sub>2<\/sub>H<sub>6<\/sub>, C<sub>3<\/sub>H<sub>8<\/sub>, C<sub>3<\/sub>H<sub>6<\/sub>, C<sub>2<\/sub>H<sub>2<\/sub> and CH<sub>4<\/sub><br \/>\nAnswer:<br \/>\nAddition reactions take place only in unsaturated hydrocarbons. So addition reaction take place only in C<sub>3<\/sub>H<sub>6<\/sub> and C<sub>2<\/sub>H<sub>2<\/sub>.<\/p>\n<p>Question 14<br \/>\nGive a test that can be used to differentiate chemically between butter and cooking oil.<br \/>\nAnswer:<br \/>\nButter is a saturated carbon compound while cooking oil is an unsaturated carbon compound. An unsaturated compound decolourises bromine water, while a saturated compound cannot decolourise it. So we can distinguish chemically between a cooking oil and butter by the bromine water. Add bromine water to a little of cooking oil and butter taken in separate test-tubes.<\/p>\n<ul>\n<li>Cooking oil decolourises bromine water showing that it is an unsaturated compound.<\/li>\n<li>Butter does not decolourise bromine water showing that it is a saturated compound.<\/li>\n<\/ul>\n<p>Question 15<br \/>\nExplain the mechanism of the cleaning action of soaps.<br \/>\nOR<br \/>\nExplain the cleansing action of soaps.<strong> [CBSE 2015 (Delhi)]<\/strong><br \/>\nAnswer:<br \/>\nWhen a dirty cloth is put in water containing dissolved soap, then the hydrocarbon end of the soap molecules in micelle attach to the oil or grease particles present on the surface of dirty cloth. In this way the soap micelle entraps the oily or greasy particles by using its hydrocarbon ends. The ionic ends of the soap molecules in the micelles, however, remain attached to water. When the dirty cloth is agitated in soap solution, the oily and greasy particles present on its surface and entrapped by soap micelles get dispersed in water due to which the soap water becomes dirty but the cloth gets cleaned. The cloth is cleaned thoroughly by rinsing in clean water a number of times.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100724\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Textbook-Chapter-End-Questions-Q15.png?resize=268%2C253&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Textbook Chapter End Questions Q15\" width=\"268\" height=\"253\" data-recalc-dims=\"1\" \/><\/p>\n<table border=\"1&quot;\">\n<tbody>\n<tr>\n<td><strong>Board<\/strong><\/td>\n<td>CBSE<\/td>\n<\/tr>\n<tr>\n<td><strong>Textbook<\/strong><\/td>\n<td>NCERT<\/td>\n<\/tr>\n<tr>\n<td><strong>Class<\/strong><\/td>\n<td>Class 10<\/td>\n<\/tr>\n<tr>\n<td><strong>Subject<\/strong><\/td>\n<td>Science<\/td>\n<\/tr>\n<tr>\n<td><strong>Chapter<\/strong><\/td>\n<td>Chapter 4<\/td>\n<\/tr>\n<tr>\n<td><strong>Chapter Name<\/strong><\/td>\n<td>Carbon and its Compounds<\/td>\n<\/tr>\n<tr>\n<td><strong>Number of Questions Solved<\/strong><\/td>\n<td>28<\/td>\n<\/tr>\n<tr>\n<td><strong>Category<\/strong><\/td>\n<td><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-2\/\">NCERT Solutions<\/a><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h3>NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds<\/h3>\n<p>Carbon compounds: Covalent bonding in carbon compounds, Versatile nature of carbon, Homologous series, Nomenclature of carbon compounds containing functional groups, (halogens, alcohol, ketones, aldehydes, alkanes, and alkynes), difference between saturated hydrocarbons and unsaturated hydrocarbons. Chemical properties of carbon compounds (combustion, oxidation, addition and substitution reaction). Ethanol\u00a0(only properties and uses), Ethanoic acid (only properties and uses), soaps and detergents.<\/p>\n<p><a class=\"button-blue\" title=\"Buy Now Formulae Handbook for CBSE Class 10 Maths and Science\" href=\"https:\/\/goo.gl\/L2Txmv\">Formulae Handbook for Class 10 Maths and Science<\/a><\/p>\n<p>Question 1<br \/>\nWhat would be the electron dot structure of carbon dioxide which has the formula CO<sub>2<\/sub>?<br \/>\nSolution:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100725\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q1.jpg?resize=147%2C57&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Q1\" width=\"147\" height=\"57\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 2<br \/>\nWhat would be the electron dot structure of a molecule of sulphur, which is made up of eight atoms of sulphur? (Hint \u2013 The eight atoms of sulphur are joined together in the form of a ring.)<br \/>\nSolution:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100726\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q2.jpg?resize=192%2C166&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Q2\" width=\"192\" height=\"166\" data-recalc-dims=\"1\" \/><\/p>\n<p>More Resources<\/p>\n<ul>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-2\/\">NCERT Solutions<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-class-10-science\/\">NCERT Solutions for Class 10 Science<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-class-10-math-solutions\/\">NCERT Solutions for Class 10 Maths<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/cbse-class-10-social-science-sst-questions-and-answers\/\">NCERT Solutions for Class 10 Social<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-10-english-literature\/\">NCERT Solutions for Class 10 English<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-class-10-hindi\/\">NCERT Solutions for Class 10 Hindi<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-class-10th-sanskrit\/\">NCERT Solutions for Class 10 Sanskrit<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-class-10-foundation-information-technology\/\">NCERT Solutions for Class 10 Foundation of IT<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/rd-sharma-class-10-solutions\/\">RD Sharma Class 10 Solutions<\/a><\/li>\n<\/ul>\n<p>Question 3<br \/>\nHow many structural isomers can you draw for pentane?<br \/>\nSolution:<br \/>\nWe can draw 3 structural isomers for pentane.<\/p>\n<p>Question 4<br \/>\nWhat are the two properties of carbon that lead to the huge number of carbon compounds we see around us?<br \/>\nSolution:<br \/>\nDue to its large valency, carbon atoms can form covalent bonds with a number of carbon atoms as well as with a large number of other atoms such as hydrogen, oxygen, nitrogen, sulphur, chlorine and many more atoms. This leads to the formation of a large number of organic compounds.<\/p>\n<p><a href=\"https:\/\/drive.google.com\/uc?export=download&amp;id=1rcTs7UbVCO82e4XL3B8HhKtwxls6SvwU\">Download NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds PDF<\/a><\/p>\n<p>Question 5<br \/>\nWhat will be the formula and electron dot structure of Cyclopentane?<br \/>\nSolution:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100727\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q5.jpg?resize=562%2C377&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Q5\" width=\"562\" height=\"377\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q5.jpg?w=562&amp;ssl=1 562w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q5.jpg?resize=300%2C201&amp;ssl=1 300w\" sizes=\"(max-width: 562px) 100vw, 562px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 6<br \/>\nDraw the structures for the following compounds.<br \/>\ni. Ethanoic acid<br \/>\nii. Bromopentane<br \/>\niii. Butanone<br \/>\niv. Hexanal<br \/>\nSolution:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100728\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q6.jpg?resize=402%2C508&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Q6\" width=\"402\" height=\"508\" srcset=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q6.jpg?w=402&amp;ssl=1 402w, https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q6.jpg?resize=237%2C300&amp;ssl=1 237w\" sizes=\"(max-width: 402px) 100vw, 402px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 7<br \/>\nHow would you name the following compounds?<br \/>\nSolution:<br \/>\ni. Ethyl bromide<br \/>\nii. Formaldehyde<br \/>\niii. Hexyne<\/p>\n<p>Question 8<br \/>\nWhy is the conversion of ethanol to Ethanoic acid an oxidation reaction?<br \/>\nSolution:<br \/>\nThe conversion of ethanol into ethanoic acid is called an oxidation reaction because oxygen is added to it during this conversion.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100729\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q8.jpg?resize=445%2C62&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Q8\" width=\"445\" height=\"62\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q8.jpg?w=445&amp;ssl=1 445w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q8.jpg?resize=300%2C42&amp;ssl=1 300w\" sizes=\"(max-width: 445px) 100vw, 445px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 9<br \/>\nA mixture of oxygen and ethyne is burnt for welding. Can you tell why a mixture of ethyne and air is not used?<br \/>\nSolution:<br \/>\nWhen a mixture of oxygen and ethyne is burnt, it burns completely producing a blue flame. This blue flame is extremely hot which produced a very high temperature which is used for welding metals. But the mixture of ethyne and air is not used for welding purposes because burning of ethyne in air produces a sooty flame, which is not enough to melt metals for welding.<\/p>\n<p>Question 10<br \/>\nWhat are oxidizing agents?<br \/>\nSolution:<br \/>\nOxidizing agents are the substances that gain electrons in an redox reaction and whose oxidation number is reduced.<\/p>\n<p>Question 11<br \/>\nExplain the nature of the covalent bond using the bond formation of CH<sub>3<\/sub>Cl.<br \/>\nSolution:<br \/>\nCH<sub>3<\/sub>Cl(methyl chloride) is made up of one carbon atom, three hydrogen atoms and one chlorine atom. Carbon atom has 4 valence electrons, each hydrogen atom has one valence electron, and a chlorine atom has 7 valence electrons. Carbon atom shares its four valence electrons with three hydrogen atoms and 1 chlorine atom to form methyl chloride as follows:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100730\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q11.jpg?resize=420%2C84&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Q11\" width=\"420\" height=\"84\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q11.jpg?w=420&amp;ssl=1 420w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q11.jpg?resize=300%2C60&amp;ssl=1 300w\" sizes=\"(max-width: 420px) 100vw, 420px\" data-recalc-dims=\"1\" \/><br \/>\nFrom the above reaction, in the dot structure of methyl chloride (CH<sub>3<\/sub>Cl) there are four pairs of shared electrons between carbon and other atoms. Each pair of shared electrons constitutes one single covalent bond. So, methyl chloride has four single covalent bonds.<\/p>\n<p>Question 12<br \/>\nDraw the electron dot structures for-<br \/>\nSolution:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100731\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q12.jpg?resize=313%2C298&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Q12\" width=\"313\" height=\"298\" srcset=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q12.jpg?w=313&amp;ssl=1 313w, https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q12.jpg?resize=300%2C286&amp;ssl=1 300w\" sizes=\"(max-width: 313px) 100vw, 313px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 13<br \/>\nWhat is a homologous series? Explain with an example.<br \/>\nSolution:<br \/>\nHomologous series is a series of compounds with a similar general formula, possessing similar chemical properties due to the presence of the same functional group, and shows a gradation in physical properties as a result of increase in molecular size and mass. For example, methane has a lower boiling point than ethane since it has more intermolecular forces with neighbouring molecules. This is because of the increase in the number of atoms making up the molecule.<\/p>\n<p>Question 14<br \/>\nHow can ethanol and Ethanoic acid be differentiated on the basis of their physical and chemical properties?<br \/>\nSolution:<br \/>\n(i) Ethanol has a pleasant smell whereas ethanoic acid has the smell of vinegar.<br \/>\n(ii) Ethanol has a burning taste whereas ethanoic acid has a sour taste.<br \/>\n(iii) Ethanol has no action on litmus paper whereas ethanoic acid turns blue litmus paper red.<br \/>\n(iv) Ethanol has no reaction with sodium hydrogencarbonate but Ethanoic acid gives brisk effervescence with sodium hydrogencarbonate.<\/p>\n<p>Question 15<br \/>\nWhy does micelle formation take place when soap is added to water? Will a micelle be formed in other solvents such as ethanol also?<br \/>\nSolution:<br \/>\nMicelle formation takes place when soap is added to water. This is because when soap is added to water in which dirty clothes are soaked, the two parts of the soap molecule dissolves in two different mediums. The organic tail dissolves in the dirt, grime or grease and the ionic head dissolves in water. When the clothes are rinsed or agitated, the dirt gets pulled out of the clothes in the water by the soap molecule. In this way the soap does its cleaning work on dirty and grimy clothes or hands.<br \/>\nThe soap molecules actually form a closed structure because of mutual repulsion of the positively charged heads. This structure is called a micelle.<\/p>\n<p>Question 16<br \/>\nWhy are carbon and its compounds used as fuels for most applications?<br \/>\nSolution:<br \/>\nCarbon and its compounds are used as fuels for most of the applications because they burn in air releasing a lot of heat energy.<\/p>\n<p>Question 17<br \/>\nExplain the formation of scum when hard water is treated with soap.<br \/>\nSolution:<br \/>\nThe precipitate form of scum is formed when soap is used for washing clothes. With hard water, a large amount of soap is wasted in reacting with the calcium and magnesium ions of hard water to form an insoluble precipitate. The precipitate form formed by the action of hard water on soap, sticks to the clothes being washed and interferes with the cleaning ability of the additional soap. This makes the cleaning of clothes difficult.<\/p>\n<p>Question 18<br \/>\nWhat change will you observe if you test soap with litmus paper (red and blue)?<br \/>\nSolution:<br \/>\nSoap is the salt of a strong base (NaOH) and a weak acid (carboxylic acid), so a solution of soap in water is basic in nature. Being basic, a soap solution turns red litmus paper blue.<\/p>\n<p>Question 19<br \/>\nWhat is hydrogenation? What is its industrial application?<br \/>\nSolution:<br \/>\nIt is a class of chemical reactions in which the net result is addition of hydrogen (H<sub>2<\/sub>) to unsaturated organic compounds such as alkenes, alkynes, etc. Hydrogenation is widely applied to the processing of vegetable oils and fats. Complete hydrogenation converts unsaturated fatty acids to saturated ones.<\/p>\n<p>Question 20<br \/>\nC<sub>2<\/sub>H<sub>5<\/sub>, C<sub>3<\/sub>H<sub>8<\/sub>, C<sub>3<\/sub>H<sub>6<\/sub>, C<sub>2<\/sub>H<sub>2<\/sub> and CH<sub>4<\/sub><br \/>\nSolution:<br \/>\nAlkenes and alkynes (unsaturated hydrocarbons) undergo addition reactions. From the above hydrocarbons C<sub>2<\/sub>H<sub>2<\/sub> is an alkyne, whereas C<sub>3<\/sub>H<sub>6<\/sub> is an alkene. So, C<sub>3<\/sub>H<sub>6<\/sub> and C<sub>2<\/sub>H<sub>2<\/sub> will undergo addition reactions.<\/p>\n<p>Question 21<br \/>\nGive a test that can be used to differentiate chemically between butter and cooking oil.<br \/>\nSolution:<br \/>\nBromine water test can be used to differentiate chemically between butter and cooking oil. Add bromine water to a little of cooking oil and butter taken in separate test tubes. &lt;font<br \/>\na. Decolourising of bromine water by cooking oil (unsaturated compound)<br \/>\nb. Butter (saturated compound) does not decolourise bromine water<\/p>\n<p>Question 22<br \/>\nExplain the mechanism of the cleaning action of soaps.<br \/>\nSolution:<br \/>\nWe all know that soap is used to remove dirt and and grime from substances. Generally dirt and grime get stuck because they have an oily component, which is difficult to remove, by plain brushing or washing by water. A soap molecule has two parts, a head and a tail i.e. the long chain organic part and the functional group \u2013COO<sup>&#8211;<\/sup> Na<sup>+<\/sup>.<br \/>\nA soap molecule has a tadpole like structure shown below.<br \/>\nThe organic part is water insoluble but is soluble in organic solvents or in oil or grease. The ionic part is soluble in water, as water is a polar solvent. When soap is added to water in which dirty clothes are soaked, the two parts of the soap molecule dissolve in two different mediums. The organic tail dissolves in the dirt, grime or grease and the ionic head dissolves in water. When the clothes are rinsed or agitated, the dirt gets pulled out of the clothes, by the soap molecule. In this way soap does its cleaning work on dirty and grimy clothes or hands.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100732\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q22.jpg?resize=376%2C235&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Q22\" width=\"376\" height=\"235\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q22.jpg?w=376&amp;ssl=1 376w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Q22.jpg?resize=300%2C188&amp;ssl=1 300w\" sizes=\"(max-width: 376px) 100vw, 376px\" data-recalc-dims=\"1\" \/><br \/>\nThe soap molecules actually form a closed structure because of mutual repulsion of the positively charged heads. This structure is called a micelle. The micelle pulls out the dirt and grime more efficiently.<\/p>\n<p>Question 23<br \/>\nWould you be able to check if water is hard by using a detergent?<br \/>\nSolution:<br \/>\nWe would not be able to check whether a sample of water is hard by using a detergent, this is because a detergent forms lather easily even with hard water.<\/p>\n<p>Question 24<br \/>\nPeople use a variety of methods to wash clothes. Usually after adding the soap, they \u2018beat\u2019 the clothes on a stone, or beat ii with a paddle, scrub with a brush or the mixture is agitated in a washing machine. Why is agitation necessary to get clean clothes?<br \/>\nSolution:<br \/>\nIt is necessary to shake to get clean clothes because the soap micelles, which entrap oily or greasy particles on the surface of dirty clothes, have to be removed from their surface. When the clothes which are wet by soap solution are beaten, the micelles containing oil or greasy dirt particles get removed from the surface of dirty clothes and go into water and the dirty cloth gets cleaned.<\/p>\n<p><strong>Multiple Choice Questions (MCQs) [1 Mark each]<\/strong><\/p>\n<p>Question 1.<br \/>\nBuckminster fullerene is an allotropic form of [NCERT Exemplar]<br \/>\n(a) phosphorus<br \/>\n(b) sulphur<br \/>\n(c) carbon<br \/>\n(d) tin<br \/>\nAnswer:<br \/>\n(c) Buckminster fullerene is an allotrope of carbon containing clusters of 60 carbon atoms joined together to form spherical molecules. Its formula isC<sub>60<\/sub> (C-sixty). It is a dark solid at room temperature and as compared to another allotropic form of carbon (diamond and graphite), it is neither very hard nor soft.<\/p>\n<p>Question 2.<br \/>\nThe hetero atoms present in<br \/>\nCH<sub>3<\/sub> &#8211; CH<sub>2<\/sub> &#8211; O &#8211; CH<sub>2<\/sub> &#8211; CH<sub>2<\/sub>Cl are [NCERT Exemplar]<br \/>\n(i) oxygen<br \/>\n(ii) carbon<br \/>\n(iii) hydrogen<br \/>\n(iv) chlorine<br \/>\n(a) (i) and (ii)<br \/>\n(b) (ii) and (iii)<br \/>\n(c) (iii) and (iv)<br \/>\n(d) (i) and (iv)<br \/>\nAnswer:<br \/>\n(d) Atoms other than C and H, if present in organic compound, are called heteroatoms.<\/p>\n<p>Question 3.<br \/>\nIn which of the following .compounds -OH is the functional group? [NCERT Exemplar]<br \/>\n(a) Butanone<br \/>\n(b) Butanol<br \/>\n(c) Butanoic<br \/>\n(d) Butanal<br \/>\nAnswer:<br \/>\n(b) Butanol, CH<sub>3<\/sub>\u2014CH<sub>2<\/sub>\u2014CH<sub>2<\/sub>\u2014CH<sub>2<\/sub>\u2014OH<br \/>\nThe general formula of alcohols is C<sub>n<\/sub>H<sub>2n+1<\/sub>\u2014 OH.<br \/>\nFor butanol, n = 4. So, formula is<br \/>\nC<sub>4<\/sub>H<sub>9<\/sub>\u2014OH or CH<sub>3<\/sub>\u2014CH<sub>2<\/sub>\u2014CH<sub>2<\/sub>\u2014CH<sub>2<\/sub>\u2014OH<\/p>\n<p>Question 4.<br \/>\nThe soap molecule has a [NCERT Exemplar]<br \/>\n(a) hydrophilic head and a hydrophobic tail<br \/>\n(b) hydrophobic head and a hydrophilic tail<br \/>\n(c) hydrophobic head and a hydrophobic tail<br \/>\n(d) hydrophilic head and a hydrophilic tail<br \/>\nAnswer:<br \/>\n(a) A soap molecule is made up of two parts- a long hydrocarbon part and a short ionic part \u2014COONa<sup>+\u00a0<\/sup> group. The long hydrocarbon chain is hydrophobic (water repelling) and ionic portion is hydrophilic (water attracting).<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100733\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q4.png?resize=223%2C63&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q4\" width=\"223\" height=\"63\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 5.<br \/>\nStructural formula of benzene is [NCERT Exemplar]<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100734\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q5.png?resize=361%2C335&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q5\" width=\"361\" height=\"335\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q5.png?w=361&amp;ssl=1 361w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q5.png?resize=300%2C278&amp;ssl=1 300w\" sizes=\"(max-width: 361px) 100vw, 361px\" data-recalc-dims=\"1\" \/><br \/>\nAnswer:<br \/>\n(c) Benzene molecule contains alternate single and . double bonds. Its formula is C<sub>6<\/sub>H<sub>6<\/sub>. In structure (b) formula is C<sub>6<\/sub>H<sub>12<\/sub>. In structure (a) double bond is not at alternate position. In (d) formula is C<sub>6<\/sub>H<sub>8<\/sub>.<\/p>\n<p>Question 6.<br \/>\nWhich of the following is not a straight chain hydrocarbon? [NCERT Exemplar]<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100735\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q6.png?resize=332%2C231&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q6\" width=\"332\" height=\"231\" srcset=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q6.png?w=332&amp;ssl=1 332w, https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q6.png?resize=300%2C209&amp;ssl=1 300w\" sizes=\"(max-width: 332px) 100vw, 332px\" data-recalc-dims=\"1\" \/><br \/>\nAnswer:<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100736\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q6.1.png?resize=359%2C142&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q6.1\" width=\"359\" height=\"142\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q6.1.png?w=359&amp;ssl=1 359w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q6.1.png?resize=300%2C119&amp;ssl=1 300w\" sizes=\"(max-width: 359px) 100vw, 359px\" data-recalc-dims=\"1\" \/><br \/>\nchain hydrocarbon not straight chain hydrocarbon. Rest three are straight chain hydrocarbons.<\/p>\n<p>Question 7.<br \/>\nWhich among the following are unsaturated hydrocarbons? [NCERT Exemplar]<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100737\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q7.png?resize=242%2C154&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q7\" width=\"242\" height=\"154\" data-recalc-dims=\"1\" \/><br \/>\n(a) (i) and (iii)<br \/>\n(b) (ii) and (iii)<br \/>\n(c) (ii) and (iv)<br \/>\n(d) (iii) and (iv)<br \/>\nAnswer:<br \/>\n(c) Unsaturated hydrocarbons have double or triple bond in the structure. Both (ii) and (iv) structures have triple and double carbon-carbon bonds respectively.<\/p>\n<p>Question 8.<br \/>\nChlorine reacts with saturated hydrocarbons at room temperature in the [NCERT Exemplar]<br \/>\n(a) absence of sunlight<br \/>\n(b) presence of sunlight<br \/>\n(c) presence of water<br \/>\n(d) presence of hydrochloric acid<br \/>\nAnswer:<br \/>\n(b) Chlorine reacts with saturated hydrocarbon at room temperature in the presence of sunlight.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100738\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q8.png?resize=332%2C65&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q8\" width=\"332\" height=\"65\" srcset=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q8.png?w=332&amp;ssl=1 332w, https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q8.png?resize=300%2C59&amp;ssl=1 300w\" sizes=\"(max-width: 332px) 100vw, 332px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 9.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100739\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q9.png?resize=343%2C62&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q9\" width=\"343\" height=\"62\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q9.png?w=343&amp;ssl=1 343w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q9.png?resize=300%2C54&amp;ssl=1 300w\" sizes=\"(max-width: 343px) 100vw, 343px\" data-recalc-dims=\"1\" \/><br \/>\nIn the above given reaction, alk.KMnO<sub>4<\/sub> acts as [NCERT Exemplar]<br \/>\n(a) reducing agent<br \/>\n(b) oxidising agent<br \/>\n(c) catalyst agent<br \/>\n(d) dehydrating<br \/>\nAnswer:<br \/>\n(b) KMnO<sub>4<\/sub> acts as oxidising agent, because it removes hydrogen from CH<sub>3<\/sub>CH<sub>2<\/sub>OH and adds one oxygen to it.<\/p>\n<p>Question 10.<br \/>\nButanone is a four carbon compound with functional group [NCERT Exemplar]<br \/>\n(a) carboxylic acid<br \/>\n(b) aldehyde<br \/>\n(c) ketone<br \/>\n(d) alcohol<br \/>\nAnswer:<br \/>\n(c) In butanone, the functional group is<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100740\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q10.png?resize=170%2C36&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q10\" width=\"170\" height=\"36\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 11.<br \/>\nIdentify the unsaturated compounds from the following [NCERT Exemplar]<br \/>\n(i) Propane<br \/>\n(ii) Propene<br \/>\n(iii) Propyne<br \/>\n(iv) Chloropropane<br \/>\n(a) (i) and (ii)<br \/>\n(b) (ii) and (iv)<br \/>\n(c) (iii) and (iv)<br \/>\n(d) (ii) and (iii)<br \/>\nAnswer:<br \/>\n(d) Propene, CH<sub>3<\/sub>CH=CH<sub>2<\/sub> (ii) and propyne, CH<sub>3<\/sub>\u2014 C = CH (iii) both have double and triple bonds, respectively, hence are unsaturated compounds.<\/p>\n<p>Question 12.<br \/>\nWhich of the following does not belong to the same homologous series? [NCERT Exemplar]<br \/>\n(a) CH<sub>4<\/sub><br \/>\n(b) C<sub>2<\/sub>H<sub>6<\/sub><br \/>\n(c) C<sub>3<\/sub>H<sub>8<\/sub><br \/>\n(d) C<sub>4<\/sub>H<sub>8<\/sub><br \/>\nAnswer:<br \/>\n(d) Because succesive members of a homologous series differ by \u2014CH<sub>2<\/sub> unit.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100741\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q12.png?resize=78%2C78&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q12\" width=\"78\" height=\"78\" data-recalc-dims=\"1\" \/><br \/>\nThus, C<sub>4<\/sub>H<sub>10<\/sub> is the next member of this series. So, homologous series of alkanes is:<br \/>\nmethane (CH<sub>4<\/sub>), ethane (C<sub>2<\/sub>H<sub>6<\/sub>), propane (C<sub>3<\/sub>H<sub>8<\/sub>) and butane (C<sub>4<\/sub>H<sub>10<\/sub>).<br \/>\nSo, C<sub>4<\/sub>H<sub>8<\/sub> does not belong to the homologous series.<\/p>\n<p>Question 13.<br \/>\nEthane with molecular formula C<sub>2<\/sub>H<sub>6<\/sub> has [NCERT Exemplar]<br \/>\n(a) 6 covalent bonds<br \/>\n(b) 7 covalent bonds<br \/>\n(c) 8 covalent bonds<br \/>\n(d) 9 covalent bonds<br \/>\nAnswer:<br \/>\n(b) Structure formula of ethane (C<sub>2<\/sub>H<sub>6<\/sub>) is<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100742\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q13.png?resize=122%2C91&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q13\" width=\"122\" height=\"91\" data-recalc-dims=\"1\" \/><br \/>\nIt is clear that it has 7 covalent bonds.<\/p>\n<p>Question 14.<br \/>\nWhich of the following are correct structural isomers of butane? [NCERT Exemplar]<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100743\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q14.png?resize=216%2C407&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q14\" width=\"216\" height=\"407\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q14.png?w=216&amp;ssl=1 216w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q14.png?resize=159%2C300&amp;ssl=1 159w\" sizes=\"(max-width: 216px) 100vw, 216px\" data-recalc-dims=\"1\" \/><br \/>\n(a) (i) and (iii)<br \/>\n(b) (ii) and (iv)<br \/>\n(c) (i) and (ii)<br \/>\n(d) (iii) and (iv)<br \/>\nAnswer:<br \/>\n(a) Structure (i) is n-butane and structure (iii) is iso-butane. Since, molecular formula is same, only structures are different. So, (i) and (iii) are isomers while structures (ii) and (iv) have molecular formulaC<sub>4<\/sub>H<sub>8<\/sub>.<\/p>\n<p>Question 15.<br \/>\nIn the soap micelles, [NCERT Exemplar]<br \/>\n(a) the ionic end of soap is on the surface of the cluster while the carbon chain is in the interior of the cluster<br \/>\n(b) ionic end of soap is in the interior of the cluster and the carbon chain is out of the cluster<br \/>\n(c) Both ionic end and carbon chain are in the interior of the cluster<br \/>\n(d) Both ionic end and carbon chain are on the exterior of the cluster<br \/>\nAnswer:<br \/>\n(a) A \u2018spherical aggregate of soap molecules\u2019 in the soap solution in water is called a \u2018micelle\u2019. In a soap micelle, the soap molecules are arranged readily with hydrocarbon ends directed towards the centre and ionic ends directed outwards.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100744\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q15.png?resize=367%2C144&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q15\" width=\"367\" height=\"144\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q15.png?w=367&amp;ssl=1 367w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q15.png?resize=300%2C118&amp;ssl=1 300w\" sizes=\"(max-width: 367px) 100vw, 367px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Question 16.<br \/>\nVinegar is a solution of [NCERT Exemplar]<br \/>\n(a) 50% &#8211; 60% acetic acid in alcohol<br \/>\n(b) 5% &#8211; 8% acetic acid in alcohol<br \/>\n(c) 5% &#8211; 8% acetic acid in water<br \/>\n(d) 50% &#8211; 60% acetic acid in water<br \/>\nAnswer:<br \/>\n(c) A 5%-8% solution of acetic acid in water is called vinegar.<\/p>\n<p>Question 17.<br \/>\nOils on treating with hydrogen in the presence of palladium or nickel catalyst form fats. This is an example of [NCERT Exemplar]<br \/>\n(a) addition reaction<br \/>\n(b) substitution reaction<br \/>\n(c) displacement reaction<br \/>\n(d) oxidation reaction<br \/>\nAnswer:<br \/>\n(a) Oils are unsaturated compounds containing double bonds. Addition reactions are characteristic property of unsaturated hydrocarbons. The given reaction is an example of addition reaction.<\/p>\n<p>Question 18.<br \/>\nCarbon forms four covalent bonds by sharing its four valence electrons with four univalent atoms, e.g. hydrogen. After the formation of four bonds, carbon attains the electronic configuration of [NCERT Exemplar]<br \/>\n(a) helium<br \/>\n(b) neon<br \/>\n(c) argon<br \/>\n(d) krypton<br \/>\nAnswer:<br \/>\n(b) Electronic configuration of carbon (C) = 2, 4 when it forms four covalent bonds by sharing its four valence electrons with hydrogen, it forms CH<sub>4<\/sub> molecule like this<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100745\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q18.png?resize=213%2C92&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q18\" width=\"213\" height=\"92\" data-recalc-dims=\"1\" \/><br \/>\nNow, electronic configuration of C in CH<\/p>\n<p><sub>4<\/sub> = 2, 8.<br \/>\nAtomic number of Ne is 10. Its electronic K L configuration is 2,8. Therefore, after the formation of four bonds, carbon attains the electronic configuration of neon.<\/p>\n<p>Question 19.<br \/>\nMineral acids are stronger acids than carboxylic acids because<br \/>\n(i) mineral acids are completely ionised.<br \/>\n(ii) carboxylic acids are completely ionised.<br \/>\n(iii) mineral acids are partially ionised.<br \/>\n(iv) carboxylic acids are partially ionised.<br \/>\n(a) (i) and (iv)<br \/>\n(b) (ii) and (iii)<br \/>\n(c) (i) and (ii)<br \/>\n(d) (iii) and (iv)<br \/>\nAnswer:<br \/>\n(a) Mineral acids are strong acids which ionise almost completely and carboxylic acids are weak acids which ionise only pardally.<\/p>\n<p>Question 20.<br \/>\nWhile cooking, if the bottom of the vessel is getting blackened on the outside, it means that [NCERT Exemplar]<br \/>\n(a) food is not cooked completely<br \/>\n(b) the fuel is not burning completely<br \/>\n(c) fuel is wet<br \/>\n(d) fuel is burning completely<br \/>\nAnswer:<br \/>\n(b) The unburnt particles of the fuel present in smoke blacken the vessel from outside.<\/p>\n<p>Question 21.<br \/>\nThe reaction in which a reagent (partially or completely) replaces atom or group of atoms from saturated compounds or A are called B reaction.<br \/>\nHere, A and B respectively refers to<br \/>\n(a) unsaturated compounds, addition<br \/>\n(b) unsaturated compounds, substitution<br \/>\n(c) benzene, substitution<br \/>\n(d) alkene, addition<br \/>\nAnswer:<br \/>\n(c) Substitution reaction is usually given by saturated compounds and benzene. Unsaturated compounds usually give addition reactions.<\/p>\n<p>Question 22.<br \/>\nThe table gives information about some esters and the fragrance they produce.<\/p>\n<table style=\"height: 247px;\" border=\"2\" width=\"280\">\n<tbody>\n<tr>\n<td style=\"text-align: center;\" width=\"98\">Ester<\/td>\n<td style=\"text-align: center;\" width=\"75\">Fragrance<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"98\">Ethyl methanoate<\/td>\n<td style=\"text-align: center;\" width=\"75\">Rum<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"98\">Methyl butanoate<\/td>\n<td style=\"text-align: center;\" width=\"75\">Apple<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"98\">Ethyl butanoate<\/td>\n<td style=\"text-align: center;\" width=\"75\">Pineapple<\/td>\n<\/tr>\n<tr>\n<td style=\"text-align: center;\" width=\"98\">Propyl ethanoate<\/td>\n<td style=\"text-align: center;\" width=\"75\">Pear<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p style=\"text-align: left;\">Which structure do the ester compounds in the table have in common?<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100746\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q22.png?resize=346%2C115&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds MCQs Q22\" width=\"346\" height=\"115\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q22.png?w=346&amp;ssl=1 346w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-MCQs-Q22.png?resize=300%2C100&amp;ssl=1 300w\" sizes=\"(max-width: 346px) 100vw, 346px\" data-recalc-dims=\"1\" \/><br \/>\nAnswer:<br \/>\n(d) All esters have the common structure of carboxylic group represented by the suffix date.<\/p>\n<h2><a id=\"Carbon_and_Its_Compounds_Class_10_in_Hindi\"><\/a>NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds (Hindi Medium)<\/h2>\n<p><img loading=\"lazy\" class=\"aligncenter size-full wp-image-86779\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-1.png?resize=540%2C661&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 1\" width=\"540\" height=\"661\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-1.png?w=540&amp;ssl=1 540w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-1.png?resize=245%2C300&amp;ssl=1 245w\" sizes=\"(max-width: 540px) 100vw, 540px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86780\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-2.png?resize=539%2C675&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 2\" width=\"539\" height=\"675\" srcset=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-2.png?w=539&amp;ssl=1 539w, https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-2.png?resize=240%2C300&amp;ssl=1 240w\" sizes=\"(max-width: 539px) 100vw, 539px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86781\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-3.png?resize=539%2C705&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 3\" width=\"539\" height=\"705\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-3.png?w=539&amp;ssl=1 539w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-3.png?resize=229%2C300&amp;ssl=1 229w\" sizes=\"(max-width: 539px) 100vw, 539px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86782\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-4.png?resize=537%2C658&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 4\" width=\"537\" height=\"658\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-4.png?w=537&amp;ssl=1 537w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-4.png?resize=245%2C300&amp;ssl=1 245w\" sizes=\"(max-width: 537px) 100vw, 537px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86783\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-5.png?resize=534%2C702&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 5\" width=\"534\" height=\"702\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-5.png?w=534&amp;ssl=1 534w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-5.png?resize=228%2C300&amp;ssl=1 228w\" sizes=\"(max-width: 534px) 100vw, 534px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86784\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-6.png?resize=537%2C696&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 6\" width=\"537\" height=\"696\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-6.png?w=537&amp;ssl=1 537w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-6.png?resize=231%2C300&amp;ssl=1 231w\" sizes=\"(max-width: 537px) 100vw, 537px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86785\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-7.png?resize=535%2C680&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 7\" width=\"535\" height=\"680\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-7.png?w=535&amp;ssl=1 535w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-7.png?resize=236%2C300&amp;ssl=1 236w\" sizes=\"(max-width: 535px) 100vw, 535px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86786\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-8.png?resize=542%2C673&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 8\" width=\"542\" height=\"673\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-8.png?w=542&amp;ssl=1 542w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-8.png?resize=242%2C300&amp;ssl=1 242w\" sizes=\"(max-width: 542px) 100vw, 542px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86787\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-9.png?resize=541%2C656&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 9\" width=\"541\" height=\"656\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-9.png?w=541&amp;ssl=1 541w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-9.png?resize=247%2C300&amp;ssl=1 247w\" sizes=\"(max-width: 541px) 100vw, 541px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86788\" src=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-10.png?resize=538%2C674&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 10\" width=\"538\" height=\"674\" srcset=\"https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-10.png?w=538&amp;ssl=1 538w, https:\/\/i2.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-10.png?resize=239%2C300&amp;ssl=1 239w\" sizes=\"(max-width: 538px) 100vw, 538px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86789\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-11.png?resize=537%2C649&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 11\" width=\"537\" height=\"649\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-11.png?w=537&amp;ssl=1 537w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-11.png?resize=248%2C300&amp;ssl=1 248w\" sizes=\"(max-width: 537px) 100vw, 537px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86790\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-12.png?resize=541%2C708&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 12\" width=\"541\" height=\"708\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-12.png?w=541&amp;ssl=1 541w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-12.png?resize=229%2C300&amp;ssl=1 229w\" sizes=\"(max-width: 541px) 100vw, 541px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86791\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-13.png?resize=538%2C702&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 13\" width=\"538\" height=\"702\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-13.png?w=538&amp;ssl=1 538w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-13.png?resize=230%2C300&amp;ssl=1 230w\" sizes=\"(max-width: 538px) 100vw, 538px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86792\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-14.png?resize=538%2C675&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 14\" width=\"538\" height=\"675\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-14.png?w=538&amp;ssl=1 538w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-14.png?resize=239%2C300&amp;ssl=1 239w\" sizes=\"(max-width: 538px) 100vw, 538px\" data-recalc-dims=\"1\" \/><br \/>\n<img loading=\"lazy\" class=\"aligncenter size-full wp-image-86793\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-15.png?resize=542%2C651&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and Its Compounds Hindi Medium 15\" width=\"542\" height=\"651\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-15.png?w=542&amp;ssl=1 542w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/07\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-Its-Compounds-Hindi-Medium-15.png?resize=250%2C300&amp;ssl=1 250w\" sizes=\"(max-width: 542px) 100vw, 542px\" data-recalc-dims=\"1\" \/><\/p>\n<h3><a id=\"Class_10_Carbon_and_its_Compounds_Mind_Map\"><\/a>Class 10 Science Carbon and its Compounds Mind Map<\/h3>\n<p>Carbon is an important constituent of the foods, fuels, household and commercial articles, textile fabrics, perfumes, explosives, dyes, war gases etc. The Earth&#8217;s crust has only 0.02% carbon in the form of minerals (like petroleum, coal, carbonates and hydrogen carbonates) and the atmosphere comprises of only 0.03% of carbon dioxide<\/p>\n<p><strong>Allotropes of Carbon<\/strong><br \/>\nAn element, in different forms, having different physical properties but similar chemical properties is known as allotropes of that element.<br \/>\nCarbon has three well known allotropes which are graphite, diamond and buck minster fullerene.<br \/>\n<strong>Graphite:<\/strong><\/p>\n<ul>\n<li>In graphite, each carbon atom is bonded to three other carbon atoms in the same plane giving a hexagonal array.<\/li>\n<li>One of these bonds is a double-bond, and thus the valency of carbon is satisfied.<\/li>\n<li>Graphite structure is formed by the hexagonal arrays being placed in layers one above the other.<\/li>\n<li>Unlike other non-metals graphite is a very good conductor of electricity.<\/li>\n<\/ul>\n<p><strong>Diamond:<\/strong><\/p>\n<ul>\n<li>In diamond, each carbon atom is bonded to four other carbon atoms forming a rigid three-dimensional structure.<\/li>\n<li>Diamond is the hardest substance known while graphite is smooth and slippery.<\/li>\n<li>Diamonds can be synthesized by subjecting pure carbon to very high pressure and temperature.<\/li>\n<li>These synthetic diamonds are small but are otherwise indistinguishable from natural diamonds.<\/li>\n<\/ul>\n<p><strong>Fullerene:<\/strong><br \/>\nThis is another class of carbon allotropes. The first one to be identified was C-60 which has carbon atoms arranged in the shape of a football. Since this looked like the geodesic dome designed by the US architect Buckminster Fuller, the molecule was named fullerene.<\/p>\n<p><strong>Saturated and Unsaturated Hydrocarbons<\/strong><br \/>\n<strong>Saturated hydrocarbons:<\/strong> Compounds in which carbon- carbon atoms &amp; carbon-hydrogen atoms are held together by single bonds. General formula is C<sub>n<\/sub>H<sub>2n+2<\/sub>.<br \/>\n<strong>Unsaturated hydrocarbons:<\/strong> Compounds consist of a single, double or triple bond between carbon-carbon atoms.<br \/>\nThese double-bonded compounds are called alkenes &amp; the triple-bonded compounds are called alkynes.<br \/>\nThe general formula for alkenes is C<sub>n<\/sub>H<sub>2n<\/sub> &amp; for alkynes the same is C<sub>n<\/sub>H<sub>2n-2<\/sub>.<br \/>\n<strong>Cycloalkanes:<\/strong> These hydrocarbons possess one or multiple carbon rings. The hydrogen atom is attached to the carbon ring.<br \/>\n<strong>Aromatic hydrocarbons:<\/strong> These are also called as arenes. Arenes are compounds which consist of at least one aromatic ring.<\/p>\n<p><strong>Bonding in Carbon<\/strong><\/p>\n<ul>\n<li>Atomic number of carbon = 6<\/li>\n<li>Electronic configuration has 2 electrons in KL shell and 4 electrons in L shell.<\/li>\n<li>Carbon shares its four valence electrons with other atoms of carbon or with atoms of other elements. These electrons contributed by the atoms, for mutual sharing in order to acquire the stable noble gas configuration is called covalencv of that atom.<\/li>\n<li>Hence, carbon shows tetracovalency.<\/li>\n<li>The simplest molecule formed by sharing of electrons (i.e., covalent bonds), can be represented by electron dot structure.<\/li>\n<\/ul>\n<p><strong>Versatile Nature of Carbon<\/strong><\/p>\n<ul>\n<li><strong>Catenation:<\/strong> It is the unique property of self linkage of carbon atoms by means of covalent bonds to form straight chains, or branched chains, or the rings of different sizes.<\/li>\n<li><strong>Tetracovalency:<\/strong> Due to small size, and presence of four valence electrons, carbon can fonn strong bonds with other carbon atoms, hydrogen, oxygen, nitrogen, or sulphur, etc. For example, compounds of carbon with hydrogen are called hydrocarbons.<\/li>\n<li><strong>Multiple Bond Formation:<\/strong> Due to small size, it forms multiple bonds (i.e., double bonds or triple bonds) with other elements as well as with its own atoms.<\/li>\n<li><strong>Isomerism:<\/strong> The phenomenon by means of which the carbon compounds with same molecular formula show different structures, and properties.<\/li>\n<\/ul>\n<p><strong>Soaps:<\/strong> Ester of higher fatty acids is called soap. It is manufactured by the reaction of caster of higher fatty acid with sodium hydroxide. The sodium salt so formed has cleansing property.<br \/>\n<strong>Detergents:<\/strong> Soap cannot form lather in hard water. To overcome this problem, detergents were introduced. Detergent is also known as soapless soap. Detergent is sodium salt of benzene sulphonic acid or sodium salt of long chain alkyl hydrogen sulphate.<\/p>\n<p><strong>Nomenclature of Carbon Compounds: IUPAC Name<\/strong><br \/>\nRales for Nomenclature of Organic Compounds:<\/p>\n<ul>\n<li>Identify the number of carbon atoms in the compound &amp; name the compound according to the number of carbon atoms.<\/li>\n<li>If any functional group is present, add a &#8216;prefix&#8217; or &#8216;suffix&#8217; specified for the functional group with the name of the parent compound.<\/li>\n<li>Prefix is added for only Halo group and for rest of the functional groups suffix is added.<\/li>\n<li>If the name of the functional group is to be given as a suffix, the name of the carbon chain is modified by deleting the final &#8216;e&#8217; and adding the appropriate suffix.<\/li>\n<li>In the case of unsaturated hydrocarbon if double bond is present in the carbon chain, then &#8216;ene&#8217; will be added in the parent name of compound after omitting &#8216;ane&#8217; and if triple bond is present in the carbon chain, then &#8216;yne&#8217; will be added.<\/li>\n<\/ul>\n<p><strong>Properties of Ethanol<\/strong><\/p>\n<ul>\n<li style=\"list-style-type: none;\">\n<ul>\n<li style=\"list-style-type: none;\">\n<ul>\n<li>Ethanol exists in liquid state at room temperature.<\/li>\n<li>Mixture of alcohol to ethane results in the fonnation of ethanol &amp; it is the active ingredient of all alcoholic drinks. Even a small quantity of ethanol if consumed can causes drunkenness.<\/li>\n<li>Being a good solvent, it is also used in medicines like tincture of iodine, cough syrups, and many other tonics.<\/li>\n<li>Reaction with sodium &#8211;<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100747\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Mind-Map-1.png?resize=294%2C99&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Mind Map 1\" width=\"294\" height=\"99\" data-recalc-dims=\"1\" \/><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<p><strong>Properties of Ethanoic Acid<\/strong><\/p>\n<ul>\n<li style=\"list-style-type: none;\">\n<ul>\n<li style=\"list-style-type: none;\">\n<ul>\n<li>Ethanoic acid commonly known as acetic acid belongs to a group of carboxylic acids.<\/li>\n<li>Vinegar used in our day to day life is a 5-8% solution of acetic acid in water. It is extensively used as a preservative in pickles.<\/li>\n<li>Pure ethanoic acid has a melting point of290 K due to which it<br \/>\noften freezes in cold climates giving rise to its name as glacial acetic acid.<br \/>\n<img loading=\"lazy\" class=\"alignnone size-full wp-image-100748\" src=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Mind-Map-2.png?resize=314%2C54&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Mind Map 2\" width=\"314\" height=\"54\" srcset=\"https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Mind-Map-2.png?w=314&amp;ssl=1 314w, https:\/\/i0.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Mind-Map-2.png?resize=300%2C52&amp;ssl=1 300w\" sizes=\"(max-width: 314px) 100vw, 314px\" data-recalc-dims=\"1\" \/><\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<\/li>\n<\/ul>\n<ul>\n<li>Reaction with a base: NaOH + CH<sub>3<\/sub>COOH \u2192 CH<sub>3<\/sub>COONa + H<sub>2<\/sub>O<\/li>\n<li>Reaction with carbonates and hydrogen carbonates:<br \/>\n2CH<sub>3<\/sub>COOH + NA<sub>2<\/sub>CO<sub>3<\/sub> \u2192 2CH<sub>3<\/sub>COONa + H<sub>2<\/sub>O + CO<sub>2<\/sub><br \/>\nCH<sub>3<\/sub>COOH + NaHCO<sub>3<\/sub> \u2192 CH<sub>3<\/sub>COONa + H<sub>2<\/sub>O + CO<sub>2<\/sub><\/li>\n<\/ul>\n<p><strong>Homologous Series<\/strong><\/p>\n<ul>\n<li>A series of carbon compounds in which same functional group substitutes the hydrogen atom is called a homologous series.<\/li>\n<li>These compounds have similar chemical properties due to the presence of same kind of functional group. For e.g. series of alkanes i.e. methane, ethane, propane, butane and so on is a homologous series.<\/li>\n<li>Similarly the series of alkene &amp; alkynes also forms homologous series.<\/li>\n<li>The series like methanol, ethanol, propanol, butanol and so on is also a homologous series. The functional group attached to these compounds is alcohol.<\/li>\n<li>With the increase in molecular mass in a homologous series the physical properties like melting points, boiling points &amp; solubility in a particular solvent increases.<\/li>\n<li>But the chemical properties of a homologous series determined by the functional group remain same.<\/li>\n<\/ul>\n<p><strong>Chemical Properties of Carbon Compounds<\/strong><br \/>\n<strong>Combustion Reactions:<\/strong> When Carbon &amp; its compounds bum in the presence of Oxygen (or air), they give CO<sub>2<\/sub>, heat &amp; light.<br \/>\nE.g.: C + O<sub>2<\/sub> \u2192 CO<sub>2<\/sub> + Heat + Light.<br \/>\n<strong>Oxidation Reactions:<\/strong> Though combustion is generally an oxidation reaction, not all oxidation reactions are combustion reactions. Oxidation is also carried out by using oxidizing agents (Oxidants).<br \/>\n<strong>Addition reactions:<\/strong> Unsaturated organic compounds, like alkenes and alkynes, undergo addition reactions to become saturated in nature.<br \/>\nE.g. CH<sub>2<\/sub> = CH<sub>2<\/sub> + H<sub>2<\/sub> + (Nickel catalyst) \u2192 CH<sub>3<\/sub>&#8211; CH<sub>3<\/sub><br \/>\n<strong>Substitution Reaction:<\/strong> A Substitution reaction is one in which an atom or a group of atoms (functional group) in the compound are replaced by another atom ( or group of atoms). Substitution reactions are single displacement reactions.<br \/>\nE.g.: CH<sub>4<\/sub> + Cl<sub>2<\/sub> + Sunlight \u2192 CH<sub>3<\/sub>Cl + HCl<\/p>\n<p><img loading=\"lazy\" class=\"alignnone size-full wp-image-100749\" src=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Mind-Map-3.png?resize=413%2C271&#038;ssl=1\" alt=\"NCERT Solutions for Class 10 Science Chapter 4 Carbon and its Compounds Mind Map 3\" width=\"413\" height=\"271\" srcset=\"https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Mind-Map-3.png?w=413&amp;ssl=1 413w, https:\/\/i1.wp.com\/www.cbselabs.com\/wp-content\/uploads\/2019\/09\/NCERT-Solutions-for-Class-10-Science-Chapter-4-Carbon-and-its-Compounds-Mind-Map-3.png?resize=300%2C197&amp;ssl=1 300w\" sizes=\"(max-width: 413px) 100vw, 413px\" data-recalc-dims=\"1\" \/><\/p>\n<p>Now that you are provided all the necessary information regarding NCERT Solutions for class 10 Science chapter 4.\u00a0We hope this detailed article on NCERT Solutions for Class 10 Science Carbon and its compounds is helpful. If you have any query regarding this article or NCERT Solutions for Class 10 Science, leave your comments in the comment section below and we will get back to you as soon possible.<\/p>\n<div class=\"featured-snippet\">\n<h3>NCERT Solutions for Class 10 Science All Chapters<\/h3>\n<ul>\n<li><a href=\"https:\/\/www.cbselabs.com\/chemical-reactions-and-equation-cbse-class-10-science-ncert-solutions\/\">Chapter 1 Chemical Reactions and Equations<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/acids-bases-and-salts-cbse-class-10-science-ncert-solutions\/\">Chapter 2 Acids, Bases and Salts<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/metals-and-non-metals-cbse-class-10-science-ncert-solutions\/\">Chapter 3 Metals and Non-metals<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-10-science-chapter-4-carbon-and-its-compounds\/\">Chapter 4 Carbon and Its Compounds<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/periodic-classification-of-element-cbse-class-10-science-ncert-solutions\/\">Chapter 5 Periodic Classification of Elements<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-10-science-chapter-6-life-processes\/\">Chapter 6 Life Processes<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/control-and-coordination-cbse-class-10-science-ncert-solutions\/\">Chapter 7 Control and Coordination<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-class-10th-science-chapter-8-organisms-reproduce\/\">Chapter 8 How do Organisms Reproduce?<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-10th-science-chapter-9-heredity-and-evolution\/\">Chapter 9 Heredity and Evolution<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-class-10th-science-chapter-10-light-reflection-refraction\/\">Chapter 10 Light Reflection and Refraction<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-10th-science-chapter-11-the-human-eye-and-the-colourful-world\/\">Chapter 11 Human Eye and Colourful World<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-class-10-science-chapter-12-electricity\/\">Chapter 12 Electricity<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-for-class-10-science-chapter-13-magnetic-effects-of-electric-current\/\">Chapter 13 Magnetic Effects of Electric Current<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/sources-of-energy-cbse-class-10-science-ncert-solutions\/\">Chapter 14 Sources of Energy<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-class-10th-science-chapter-15-environment\/\">Chapter 15 Our Environment<\/a><\/li>\n<li><a href=\"https:\/\/www.cbselabs.com\/ncert-solutions-class-10-science-chapter-16-management-natural-resources\/\">Chapter 16 Management of Natural Resources<\/a><\/li>\n<\/ul>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Science Chapter 4 Carbon And Its Compounds:\u00a0In this article, we will provide you detailed Carbon and Its Compounds Class 10 NCERT Solutions. The\u00a0NCERT Solutions For Class 10 Science Chapter 4 Carbon And Its Compounds was solved by the best teachers in India to help the students of class 10 to &hellip;<\/p>\n","protected":false},"author":30,"featured_media":89540,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[2],"tags":[],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v17.2 (Yoast SEO v17.2) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 10 Science Chapter 4 2019-20 Session<\/title>\n<meta name=\"description\" content=\"Free download NCERT Solutions for Class 10 Science Chapter 4 Carbon And Its Compounds PDF in Hindi Medium as well as in English Medium for CBSE, Uttarakhand, Bihar, MP Board, Gujarat Board, and UP Board students, who are using NCERT Books based on updated CBSE Syllabus for the session 2019-20.\" \/>\n<meta name=\"robots\" content=\"index, follow, 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