NCERT Solutions for Class 9th Maths: Chapter 7 Triangles Exercise 7.5

Discussion in 'CBSE Class 9 Maths Help' started by saralas, May 18, 2014.

  1. saralas

    saralas Member

    ABC is a triangle. Locate a point in the interior of [​IMG]ABC which is equidistant from all the vertices of [​IMG]ABC.

    Circumcentre of a triangle is always equidistant from all the vertices of that triangle. Circumcentre is the point where perpendicular bisectors, of all the sides of triangles meet together.
    NCERT Solutions for Class 9th Maths Exercise  7.5 Q1.JPG


    As here in [​IMG]ABC we can find the circumcentre by drawing the perpendicular bisectors of sides AB, BC, and CA of this triangle. O is the point where these bisectors are meeting together. So O is point which is equidistant from all the vertices of [​IMG]ABC.
  2. saralas

    saralas Member

    In a triangle locate a point in its interior which is equidistant from all the sides of the triangle.


    The point which is equidistant from all the sides of a triangle is incenter of triangle. Incentre of triangle is the intersection point of angle bisectors of interior angles of that triangle.

    NCERT Solutions for Class 9th Maths Exercise  7.5 Q2.JPG

    Here in [​IMG]ABC we can find the incentre of this triangle by drawing the angle bisectors of interior angles of this triangle. I is the point where these angle bisectors are intersecting each other. So, I is the point, equidistant from all the sides of [​IMG]ABC.

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